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notsponge [240]
2 years ago
12

The speed of an object in space is shown in the graph.

Mathematics
1 answer:
Virty [35]2 years ago
4 0

Step-by-step explanation:

the slope is the ratio y/x (or here distance/time) indicating how many units y changes, when x changes a certain amount of units when going from one point to another.

so, we have 2 points here

(0.2, 3)

(0.4, 6)

x (or time) changes by 0.2 units (from 0.2 to 0.4).

y (or distance) changes by 3 units (from 3 to 6).

therefore, the slope is 3/0.2 = 3/(1/5) = 3/1 / 1/5 = 3×5/1×1 = 15

that means based on the graph, that the object travels 15 miles in 1 minute.

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Evaluate the function<br> Find f(-10) if f(x) = 8x – 3
erma4kov [3.2K]

Answer:

-83

Step-by-step explanation:

so plug in 10 in 8x. So it is 10*-8 -3.

-80-3=-83

8 0
2 years ago
Read 2 more answers
Find the measure of the the sides of DEF then classify it by it sides. <br> D(8,-6) E(-1,-3) F(-2,5)
Mama L [17]

Answer:

Part a) The measure of the sides of triangle DEF are

d_D_E=\sqrt{90}\ units

d_E_F=\sqrt{65}\ units

d_D_F=\sqrt{221}\ units

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}

d=\sqrt{(3)^{2}+(9)^{2}}

d_D_E=\sqrt{90}\ units

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

d=\sqrt{(5+3)^{2}+(-2+1)^{2}}

d=\sqrt{(8)^{2}+(-1)^{2}}

d_E_F=\sqrt{65}\ units

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

d=\sqrt{(5+6)^{2}+(-2-8)^{2}}

d=\sqrt{(11)^{2}+(-10)^{2}}

d_D_F=\sqrt{221}\ units

step 4

Classify the triangle by the measure of its sides

we have

d_D_E=\sqrt{90}\ units

d_E_F=\sqrt{65}\ units

d_D_F=\sqrt{221}\ units

so

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

6 0
3 years ago
Eight classmates share four pizza equally
Fantom [35]
They each get half a slice of pizza

5 0
3 years ago
Read 2 more answers
Solve the following equations;-<br><br> x - 9 /√x + 3 =1
fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1

Cross multiply ,

\sf\implies x - 9 =\sqrt{ x +3}

Squaring both sides ,

\sf\implies (x - 9)^2 = x + 3

Simplify the whole square ,

\sf\implies x^2+9^2-2.9.x = x +3 \\

\sf\implies x^2+81 - 18x = x -3

Add 3 and subtract x on both sides ,

\sf\implies x^2 -18x-x +81-3=0

Simplify ,

\sf\implies x^2 -19x +78=0

Split the middle term of the quadratic equation,

\sf\implies x^2-13x-6x+78=0

Take out common ,

\sf\implies x( x -13)-6(x-13)=0

Take out ( x -13 ) as common ,

\sf\implies ( x -13)(x-6)=0

Equate both factors to 0 ,

\sf\implies \boxed{\pink{\sf x = 13,6}}

<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> </u><u>x</u><u> is</u><u> </u><u>1</u><u>3</u><u> </u><u>or </u><u>6</u><u> </u><u>.</u>

7 0
2 years ago
In one year the perseid metor shower had a metor appear every 1/5 5 minutes on average That same year the Leonid metor shower ha
olga55 [171]

In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor shower had a meteor appear every 4 2/3 minutes on average. How many more meteors fell during the Perseid meteor shower?

Answer:

325,452 meteors

Step-by-step explanation:

We all know that :

We have 365 days in a year and in each day there are 24 hours, Likewise an hour has 60 minutes

SO, the total number of minutes in a year is :

365 × 24 × 60 = 525600 minutes

For Perseid  meteor:

1 + \frac{1}{5}  \\ \\ = 1 + 0.2 \\  \\ = 1.2

So one meteor fall at 1.2 minutes interval Thus, in a year, we will have :

1 meteor - 1.2 minutes.

x meteor - 525600 minutes.

1.2x = 525600

x = \frac{525600}{1.2}

x = 438000

∴  438,000 meteors fell during the Perseid shower.

For  Leonid meteor shower:

4 + \frac{2}{3} = 4.67

So one meteor fall at 4.67 minutes interval Thus, in a year, we will have :

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

4.67x = 525600

x = \frac{525600}{4.67}

x = 112548

112,548 meteors fell during the Leonid Shower.

Finally , the numbers of more meteors that  fell during the Perseid meteor shower is calculated by the difference in the number of Perseid meteor shower and Lenoid meteor shower. i.e

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

5 0
3 years ago
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