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PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

so

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Albert deposits $2785 in an account that earns 3.9% interest compounded monthly. this function models the amount in the account

Step2247 [10]

The amount for the given data is found as, $\rm a = 2825(1+\frac{3.9}{12} )^{12t}$ .The given expression is true.

<h3>What is the amount?</h3>

The complete repayment of money at the end of the period for which it was borrowed is referred to as the amount.

The given data in the problem is;

P is the annual payment=2827

r is the rate of interest = 3.9%

n is the time period=12

The formula for the amount is found as;

$\rm a = p(1+\frac{r}{n} )^{nt}$

Substitute the given value;

$\rm a = 2825(1+\frac{3.9}{12} )^{12t}$

Hence the given expression is true.

To learn more about the amount, refer to the link: brainly.com/question/12184047.

#SPJ1

5 0

2 years ago

M thanks for th help

tangare [24]

Step-by-step explanation:

here's the answer to your question

4 0

3 years ago

Read 2 more answers

A scientist has discovered an organism that replicates at a rate of five per hour and lives for one week. Each replicated organi

Assoli18 [71]

At hour one, there is 1 organism. At hour two, there is five more organism. At hour three. there will be 6 x 5 = 30 more organisms, etc

This is a geometric sequence with a = 1 (i.e. number of organisms at hour one), r = 5 (number of reprications per hour).

The total number of organisms at hour seven is the sum of the first seven terms of the sequence given by a(r^n - 1)/(r - 1) = 1(5^7 - 1)/(5 - 1) = (78125 - 1)/4 = 78124/4 = 19,531

4 0

3 years ago

Brett works at a local pet store. When he works 4 hours he earns $36. When he works 9 hours he earns $81. What is the rate per h

Kitty [74]

The answer is 9 Dollars per hour because 36 divided by 9 is 4 and 9 times 9 is 81.

4 0

3 years ago