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anygoal [31]
3 years ago
7

How many push-up does he need to do each month

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer: 500

Step-by-step explanation:

2 sets of 25 pushups in 1 month

He does it ten times per month

2*25*10

500

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.35 times .7 pls show work.
Semenov [28]
Hereeeeeeeeeeeeeeeeeeeeeeee

3 0
3 years ago
Read 2 more answers
For each red t-shirt they manufacture, they should manufacture 4 blue t-shirts. The ratio of the number of the red t-shirts to t
Marta_Voda [28]

Answer: there should be 3 hope this helps

Step-by-step explanation:

6 0
3 years ago
Tyree bought a collectible comic book for $49.62 last year. this year, he sold it for $52.10. find the percent of change of the
lidiya [134]
52.10-49.62=2.48
2.48/49.62 x 100 = 4.998%
The percentage increase in the price is approximately 5 %
3 0
3 years ago
Two integers have a sum of -44 and a difference of 22. The greater of the two integers is
Leni [432]

Answer:

  -11

Step-by-step explanation:

The generic solution to ...

  • a + b = sum
  • a - b = difference

Can be found by adding the two equations:

  (a+b) + (a-b) = (sum) + (difference)

  2a = (sum + difference)

  a = (sum + difference)/2

___

Our particular solution is ...

  a = (-44 +22)/2 = -11

The greater of the two numbers is -11.

___

The other number is -33.

5 0
3 years ago
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
  12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
3 years ago
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