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Alchen [17]
3 years ago
12

Large number of particles constitute​

Physics
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

I didn't get your question

Would you mind posting the full question

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The second hand on a clock is 3.00 cm long. What is the speed of the outermost tip of that second hand
Gnom [1K]

In 60 minutes or 3600 seconds, the tip of the minute hand traverses the circumference of a circle with radius 3.00 cm, so it moves with a tangential speed of

(3.00 cm)/(3600 s) ≈ 0.00083 cm/s = 8.3 μm/s

4 0
3 years ago
A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material,
Ad libitum [116K]

This question is incomplete, the complete question is;

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors

a) (In2)R

b) 4R

c) R/(In2)

d) 2R

e) R

Answer: Option e) R is the correct answer.

Explanation:

Given that;

Inner radius = a

Outer radius = b

Conical Cylinder

∫dR = ∫(edr/2πrL)

R = e/2πL In e |ᵇₐ

R = e/2πL In(b/a) ------------- let this be equation 1

Taking a look at the second cone

a' = 2a

b' = 2a

R' = e/2πL In(2b/2a)

{L = L'}

R' = e/2πL In(b/a) -------let this be equation 2

now lets compare the two equation

R = e/2πL In(b/a)

R' = e/2πL In(b/a)

so R' = R

Therefore Option e) R is the correct answer.

8 0
3 years ago
A listener is sitting somewhere on the line between two loudspeakers that are 10 m apart. The speakers are each emitting a sine
prohojiy [21]

Answer:

57.17 Hz 114.34 Hz 285 Hz

Explanation:

The distance between the men and 1 speaker = 3.5 m

Distance between the men and second speaker = 10-3.5= 6.5 m

Here at this point there will be no sound so there will be destructive interference

Path difference \Delta x=6.5-3.5=3

We know that for destructive interference \Delta x=(2m+1)\frac{\lambda }{2}=(2m+1)\frac{v}{2f}

3=(2m+1)\frac{v}{2f}

f=(2m+1)\frac{v}{6} here v is the speed of sound in air

So for m =0

f=(2\times 0+1)\frac{343}{6}=57.17H

for m =1

f=(2\times 1+1)\frac{343}{6}=114.34Hz

for m=2

f=(2\times 2+1)\frac{343}{6}=285Hz

 

6 0
3 years ago
A car starts at zero and gets to 50 km/hour in 10 minutes. What is the initial velocity?
gladu [14]
The initial velocity is the speed and direction of the car at the beginning
of the event. 

You just said that the car "starts at zero".  You might mean that it starts at
"location zero".   But then you go on to tell us its speed after 10 minutes,
so it sounds like the "zero" at which it starts is zero speed.

In that case, its initial velocity is zero.

6 0
3 years ago
A sphere with radius 1 m has temperature 10°C. It lies inside a concentric sphere with radius 2 m and temperature 28°C. The temp
Dominik [7]

Answer:T=\frac{-26}{r}+36

Explanation:

Given Temperature at r=1m is 10^{\circ}C

Temperature at r=2m is 28^{\circ}C

\frac{\mathrm{d^2} T}{\mathrm{d} r^2}+\frac{2}{r}\frac{\mathrm{d} T}{\mathrm{d} r}=0

Let \frac{2}{r}\frac{\mathrm{d} T}{\mathrm{d} r}=S

\frac{\mathrm{d^2} T}{\mathrm{d} r^2}=\frac{2}{r}\frac{\mathrm{d} S}{\mathrm{d} r}

therefore \frac{2}{r}\frac{\mathrm{d} S}{\mathrm{d} r}+\frac{2}{r}S=0

\frac{2}{r}\frac{\mathrm{d} S}{\mathrm{d} r}=-\frac{-2S}{r}

solving

r^2 S=constant

substitute S value

\frac{\mathrm{d}T}{\mathrm{d}r}=\frac{c}{r^2}

Solving it we get

T=\frac{-c}{r}+c_2

Now using given condition

10=\frac{-c}{1}+c_2

28=\frac{-c}{2}+c_2

c_2=36,c=26

putting c values

T=\frac{-26}{r}+36

8 0
4 years ago
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