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Setler79 [48]
3 years ago
11

A football kicker kicks a ball with a mass of .42 kg. The average acceleration of the football was 14.8 m/s squared. How much fo

rce did the kicker supply to the football?
Physics
1 answer:
mrs_skeptik [129]3 years ago
4 0

To find the force we use the formula,

F = ma , where m is mass and a acceleration

Using the formula,

F = ma

F = 0.42 x 14.8

F = 6.216 N / 6.22 N

Hope you liked the answer !

You might be interested in
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.460 Hz. The pendulum ha
zlopas [31]

Answer:

The  moment of inertia is  I =1.0697 \ kg m^2

Explanation:

From the question we are told that

    The  frequency is  f  =  0.460 \ Hz

    The  mass of the pendulum is  m  =  2.40  \ kg

    The  location of the pivot from the center is d  =  0.380 \ m

     

Generally the period of the simple harmonic motion is mathematically represented as

        T   = 2 \pi  *  \sqrt{  \frac{I}{ m  *  g *  d  } }

Where I is the moment of inertia about the pivot point , so making I the subject of the formula it

=>    I =  [ \frac{T}{2 \pi } ]^2 *  m*  g * d

But the period of this simple harmonic motion can also be represented mathematically as

        T  =  \frac{1}{f}

substituting values

      T  =  \frac{1}{0.460}

      T  =  2.174 \ s

So

      I =  [ \frac{2.174}{2 * 3.142 } ]^2 *   2.40*  9.8 * 0.380

      I =1.0697 \ kg m^2

4 0
3 years ago
You are designing a 108 cm3 right circular cylindrical can whose manufacture will take waste into account. There is no waste in
FinnZ [79.3K]

Explanation:

It is given that,

The volume of a right circular cylindrical, V=108\ cm^3

We know that the volume of the cylinder is given by :

V=\pi r^2 h

108=\pi r^2 h    

h=\dfrac{108}{\pi r^2}............(1)

The upper area is given by :

A=32r^2+2\pi rh

A=32r^2+2\pi r\times \dfrac{108}{\pi r^2}

A=32r^2+\dfrac{216}{r}

For maximum area, differentiate above equation wrt r such that, we get :

\dfrac{dA}{dr}=64r-\dfrac{216}{r^2}

64r-\dfrac{216}{r^2}=0

r^3=\dfrac{216}{64}

r = 1.83 m

Dividing equation (1) with r such that,

\dfrac{h}{r}=\dfrac{108}{\pi r}

\dfrac{h}{r}=\dfrac{108}{\pi 1.83}

\dfrac{h}{r}=59 \pi

Hence, this is the required solution.

8 0
3 years ago
a 1600 kg car on flat ground is moving 6.25 m/s. its engine creates 1150 N forward force as the car moves 45.8 m. what is it fin
Sveta_85 [38]

Answer:

83,900 J

Explanation:

First, find the acceleration:

F = ma

1150 N = (1600 kg) a

a = 0.719 m/s²

Now find the final velocity.

Given:

Δx = 45.8 m

v₀ = 6.25 m/s

a = 0.719 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (6.25 m/s)² + 2 (0.719 m/s²) (45.8 m)

v = 10.2 m/s

Now find the final KE:

KE = ½ mv²

KE = ½ (1600 kg) (10.2 m/s)²

KE = 83,920 J

Rounded to three significant figures, the final kinetic energy is 83,900 J.

6 0
4 years ago
LVULAN
3241004551 [841]

For this case we have that by definition, the kinetic energy is given by the following formula:

k= \frac {1} {2} * m * v ^ 2

Where:

m: It is the mass

v: It is the velocity

According to the data we have to:

m = 100 \ kg\\v = 9 \frac {m} {s}

Substituting the values we have:

k = \frac {1} {2} * (100) * (9) ^ 2\\k = \frac {1} {2} * (100) * 81\\k = 50 * 81\\k = 4050

finally, the kinetic energy is 4050 \ J

Answer:

Option A

7 0
3 years ago
If your face is 62 cm in front of a plane mirror, where is the image of your face located?
timurjin [86]

Answer:

62 cm is in front of the mirror

Explanation:

This is answers

3 0
3 years ago
Read 2 more answers
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