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netineya [11]
2 years ago
9

I am working on Absolute value and i need help here are the questions

Mathematics
2 answers:
vladimir2022 [97]2 years ago
6 0
Remember
if you have |a|=b
solve for a=b and a=-b

<span>1. | 2x |=4
assume 2x=4 and 2x=-4
divide by 2
x=2 and -2

2. | x-3 |=7
assume x-3=7 and - 7
add 3 to both sides of each equation
x=10 and -4

3. | 2x+5 |=21
assume 2x+5=21 and 2x+5=-21
minus 5 both sides
2x=16 and 2x=-26
divide by 2
x=8 and x=-13

4. 3 |x+4|= 24
divide both sides by 3
|x+4|=8
assume that x+4=8 and x+4=-8
minus 4 both sides
x=4 and x=-12

5. | x+2 | = 2x+4
assume
x+2=2x+4 and x+2=-(2x+4)=-2x-4
minus 2 both sides
x=2x+4 and x=-2x-6
first one, minus 2x both sides and multiply by -1
2nd one, add 2x to both sides and divide by 3
x=-4 and -2

6.| x+7 |=0
x+7=0
minus 7
x=-7

7. 2 | x+1 | - 3 =17 </span>
add 3 to both sides
2|x+1|=20
divide both sides by 2
|x+1|=10
assume
x+1=10 and x+1=-10
minus 1 both sides
x=9 and -11





<span>1. x=-2 and x=2
2. x=-4 and x=10
3. x=-13 and x=8
4. x=-12 and x=4
5. x=-4 and -2
6. x=-7
7. </span>x=-11 and x=9
spayn [35]2 years ago
4 0
1) 2x = +/- 4 so x = +/- 2

2) x-3 = 7  OR x - 3 = -7
so x = 10 or x = -4

3)2x + 5 = 21 OR 2x + 5 = -21
so x = 8 or x = -13

4) x + 4 = 6 OR x + 4 = -6
so x = 2 or x = -10

5) x + 2 = -(2x+4) OR x + 2 = 2x + 4
x = -2 or x = -6

6) x + 7 =  0
x = -7

7) you forgot the equal sign somewhere in this problem
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Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelo
Digiron [165]

Answer: (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

Step-by-step explanation:

Transformation rule for dilation:

(x,y)\to(kx,ky) , where k = scale factor

Given : Scale factor = -\dfrac13

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)

Vertices after dilation:

(-1,6)\to(-1\times\dfrac{-1}{3},6\times\dfrac{-1}{3})=(\dfrac13,-2)

(0,9)\times(0\times-\dfrac13,9\times-\dfrac13)=(0,-3)

(6,-3)\to(6\times-\dfrac13,\ -3\times-\dfrac13)=(-2,1)

(3,-3)\to (3\times-\dfrac13,\ -3\times-\dfrac13)=(-1,1)

Hence, the coordinates of the image if the parallelogram = (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

8 0
2 years ago
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

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Answer:

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Answer:

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  1. area = \pi {r}^{2}
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