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kari74 [83]
3 years ago
13

Suppose a spider was able to create one thread that would extend from the top-right back corner of a room to the bottom-left fro

nt corner. Approximately how long would that thread need to be for the room below to the nearest tenth of a foot? The path of the spider's thread is shown with a dotted line. (Hint: You will use the Pythagorean theorem twice.)

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0

Answer:

d^2 = 30^2 + 12^2

e^2 = d^2 + 8^2

e^2 = 30^2 + 12^2 + 8^2

e = √(30^2 + 12^2 + 8^2) = 33.3 ft

vagabundo [1.1K]3 years ago
7 0

Answer:

33.3 feet to the nearest tenth.

Step-by-step explanation:

WE first need to find the length of the diagonal (d) across the bottom of the room.

d^2  = 30^2 + 12^2 = 1044.

Now applying Pythagoras theorem to the triangle whose hypotenuse (h)  is the path of the spider:

h^2 = d^2 + 8^2

= 1044 + 64

= 1108

h = √1108

= 33.3 feet.

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Answer is option b)

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

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<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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