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nikklg [1K]
3 years ago
9

HELP!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0

Answer:

3

Step-by-step explanation: set the two equations equal to each other. 5-2x=-4x+9 and you'd get x=2. insert 2 into the expression, and you'd get 1. to find the perimeter, a triangle has 3 sides. 1+1+1 =3

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Solve the inequality 2x < 6
Dima020 [189]

Answer:

x < 3

Step-by-step explanation:

2x < 6

Divide each side by 2

2x/2 < 6/2

x < 3

8 0
2 years ago
You are choosing between two health clubs. Club A offers membership for a fee of $ 19plus a monthly fee of $ 21.  Club B off
11111nata11111 [884]

Answer:

For 2 months

Step-by-step explanation:

Let after x months the cost of each health club is same,

Now, In club A,

Membership fees = $ 19,

Monthly fees = $ 21,

So, the total fees for x months = membership fees + total monthly fees for x months

= 19 + 21x

In Club B,

Membership fees = $ 23,

Monthly fees = $ 20,

So, the total fees for x months = membership fees + total monthly fees for x months

= 23 + 20x

Thus, we can write,

19 + 21x = 23 + 20x

21x - 20x = 23 - 21

x = 2

Hence, for 2 months the total cost of each health club would be same.

8 0
3 years ago
How many different values can an algebraic expression like 5+(x+2)
elena-14-01-66 [18.8K]

wb. lnehiu gliaghjnkmnafvgsbhdnjfnmydabgshdnjmfkg

5 0
3 years ago
Using t=tanx/2, write an expression for sinx and cosx in terms of t.
Dafna11 [192]

Assume 0 < <em>x</em>/2 < <em>π</em>/2. Then

tan²(<em>x</em>/2) + 1 = sec²(<em>x</em>/2)   ===>   sec(<em>x</em>/2) = √(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - <em>t</em> ²)

We also know that

sin²(<em>x</em>/2) + cos²(<em>x</em>/2) = 1   ===>   sin(<em>x</em>/2) = √(1 - cos²(<em>x</em>/2))

Recall the double angle identities:

cos(<em>x</em>) = 2 cos²(<em>x</em>/2) - 1

sin(<em>x</em>) = 2 sin(<em>x</em>/2) cos(<em>x</em>/2)

Then

cos(<em>x</em>) = 2/(1 - <em>t</em> ²) - 1 = (1 + <em>t</em> ²)/(1 - <em>t</em> ²)

sin(<em>x</em>) = 2 √(1 - 1/(1 - <em>t</em> ²)) / √(1 - <em>t</em> ²) = 2<em>t</em>/(1 - <em>t</em> ²)

7 0
2 years ago
Subtract and simplify: (10x4 – 2x + 7) – (6x4 + 2x3 – 4x2 – 1) A. 4x4 – 2x3 + 4x2 – 2x + 6 B. 4x4 + 2x3 – 4x2 – 2x + 8 C. 4x4 –
Masja [62]
(10x^4  - 2x + 7) - (6x^4 + 2x^3 - 4x^2 - 1)=

= 10x^4-2x+7-6x^4-2x^3+4x^2+1=\\\\ = 4x^4-2x^3+4x^2-2x+8
8 0
3 years ago
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