Answer:
88.51 is the minimum score needed to receive a grade of A.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73
Standard Deviation, σ = 11
We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.0793.
Calculation the value from standard normal z table, we have,

Hence, 88.51 is the minimum score needed to receive a grade of A.
Given:

x lies in the III quadrant.
To find:
The values of
.
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,




x lies in the III quadrant. So,


Now,



And,





We know that,



Therefore, the required values are
.
- The Midpoint of AB is (1,0).
Given that:
- In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).
To find:
So, according the question
We know that,
The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M (
).
Now from question,
We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.
So, we can say that
A is (3,1) or x₁ = 3 and y₁ = 1.
B (-1,-1) or x₂ = -1 and y₂ = -1.
∵ The coordinates of midpoint M (X,Y)
X = 
= 
= 2/2
X = 1.
And
Y = 
= 
= 0/2
Y = 0.
So, the midpoint of line AB is M (1,0)
To learn more about Midpoint of line, please click on the link;
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Answer:
38.8 litres
Step-by-step explanation:
22.6 + 18.7 = 41.3
41.3 - 2.5 = 38.8
38.8 litres
You can but it would be going straight up and down