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svet-max [94.6K]
3 years ago
6

How do I solve this?

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

First, let's find the area of the triangle. The Area of a triangle can be modeled as

b x h x 1/2; base = 6 and the height equals 8. 6x8=48 then don't forget to divide by 2. 48/2= 24

To find the area of a half-circle, you first need to find the area of the whole circle. Whole circle area equation = r^2 times pi. The diameter is 8 and the radius is 1/2 times the diameter, therefore the radius = 4. 4^2= 16

16pi= approximately 50.24

50.24/2= 25.12

25.12 + 16 = 41.12

The area of the figure is approximately 41.12 ft^2

Hope this helps and please mark me brainliest, it really helps!

:)

weeeeeb [17]3 years ago
6 0

Answer:

49.12 ft²

Step-by-step explanation:

The compound figure includes both a right angled triangle and a semi-circle. To find the area of the figure, it is best to find the area of both shapes then add them.

Area of semi-circle = (πr²) ÷ 2

= (3.14 × 4 × 4) ÷ 2

= 50.24 ÷ 2

= 25.12 ft²

Area of triangle = \frac{1}{2}bh

= \frac{1}{2} × 6 × 8

= 24 ft²

Area of compound figure = Area of semi-circle + Area of triangle

= 25.12 + 24

= 49.12 ft²

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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2 years ago
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4 0
3 years ago
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Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
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Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

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1/sinx = 4

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From SOH, CAH TOA

sinθ = opposite/hypotenuse

from sinx = 1/4

opposite = 1 and hypotenuse = 4

to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

adj = √15

cosx = adj/hyp = √15/4

tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

sin2x = 2(1/4)(√15/4)

sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

cos2x = 7/8

for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

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