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2 years ago

How do I solve this?

Mathematics

2 answers:

Snowcat [4.5K]2 years ago

7 0

Answer:

Step-by-step explanation:

First, let's find the area of the triangle. The Area of a triangle can be modeled as

b x h x 1/2; base = 6 and the height equals 8. 6x8=48 then don't forget to divide by 2. 48/2= 24

To find the area of a half-circle, you first need to find the area of the whole circle. Whole circle area equation = r^2 times pi. The diameter is 8 and the radius is 1/2 times the diameter, therefore the radius = 4. 4^2= 16

16pi= approximately 50.24

50.24/2= 25.12

25.12 + 16 = 41.12

The area of the figure is approximately 41.12 ft^2

Hope this helps and please mark me brainliest, it really helps!

weeeeeb [17]2 years ago

6 0

Answer:

49.12 ft²

Step-by-step explanation:

The compound figure includes both a right angled triangle and a semi-circle. To find the area of the figure, it is best to find the area of both shapes then add them.

Area of semi-circle = (πr²) ÷ 2

= (3.14 × 4 × 4) ÷ 2

= 50.24 ÷ 2

= 25.12 ft²

Area of triangle = $\frac{1}{2}$ bh

= $\frac{1}{2}$ × 6 × 8

= 24 ft²

Area of compound figure = Area of semi-circle + Area of triangle

= 25.12 + 24

= 49.12 ft²

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6 0

2 years ago

Help help I don’t really get this???

insens350 [35]

Answer:

Question 4: $y=\displaystyle -\frac{4}{5}x$

Question 5: $y=-5x-3$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope of the line and b is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

Question 4

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$ where two points that pass through the line are $(x_1,y_1)$ and $(x_2,y_2)$

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

$\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}$

Therefore, the slope of the line is $\displaystyle -\frac{4}{5}$ . Plug this into $y=mx+b$ as the slope (m):

$y=\displaystyle -\frac{4}{5}x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (b) is 0. Plug this into $y=\displaystyle -\frac{4}{5}x+b$ :

$y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x$

Question 5

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

$\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5$

Therefore, the slope is -5. Plug this into $y=mx+b$ :

$y=-5x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (b) is -3. Plug this into $y=-5x+b$ :

$y=-5x+(-3)\\y=-5x-3$