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Viefleur [7K]
3 years ago
5

Economics

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0

Answer:

True did it on gradepoint

Step-by-step explanation:

nice butt girl

xxTIMURxx [149]3 years ago
3 0
False because it’s natural so it’ll just come back
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Find 4 irrational number between 0.1 and 1.12​
Lelu [443]

I'm sorry but I do not know how to do this

5 0
3 years ago
2y - A / 3 equals a + 3 B / 4 solving for y
melamori03 [73]
To solve for y you need to first multiply both sides by 4. This will give you: 4y - 4A / 3 = A + 3B

Next you need to multiply both sides by 3: 4y - 4A = 3A + 9B

Now you need to add 4A to both sides: 4y = 7A + 9B

Now divide both sides by 4:

Y = 7A/4 + 9B/4
8 0
3 years ago
A clothing store offers customers a holiday sale of 20% off the price of x items. A customer then has an additional 15% off coup
aleksandr82 [10.1K]

Finding the equivalent multiplier, it is found that the function for the final price is:

P(x) = 0.68x.

-------------------------------------------

  • There is a holiday sale of 20% off the price of x, thus 0.8x is paid, as 1 - 0.2 = 0.8.
  • Additionally, there is a coupon of 15% off, thus, 0.85 of 0.8x is paid.
  • The equivalent multiplier is:

0.85(0.8) = 0.68

  • Thus, the function for the final price is:

P(x) = 0.68x

A similar problem is given at brainly.com/question/16999193

8 0
2 years ago
Read 2 more answers
Which equation could be used to find the perimeter of an isosceles triangle, with two sides 13 cm long, a base 10 cm long, and a
AVprozaik [17]
Its A.
because if the base is 13 and 13 and the sides are 10 cm multiply and get A.
4 0
3 years ago
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
scoundrel [369]

Answer:

Tan(b°) = 3/4 = three fourths (C)

Step-by-step explanation:

Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°

We would apply SOHCAHTOA from trigonometry to determine the value for each sides.

For ∆JKL

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4

From the above we know the value of each sides of ∆JKL

Find attached the diagram of the above triangle (1)

∆JKL is dilated by a scale factor = 2

Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:

Opposite = 2(3) = 6

Adjacent = 2(4) = 8

Hypotenuse = 2(5) = 10

To find tan(b°) of the new triangle, we would apply tangent ratio

Tan(b°) = opposite/adjacent

Tan(b°) = 6/8

Tan(b°) = 3/4

Find attached the diagram for the new triangle (2)

Diagram 3 shows the drawing of both triangles together.

From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.

Therefore, tan(b°) = three fourths (C)

6 0
3 years ago
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