We'll be looking for time here.
s=d/t
ts=d
t=d/s
------------------------
Average speed is:
s=(55m)/h
Distance is:
200m
---------------------------
t=(200m)/(55m/h)
t=(200m/1)*(h/(55m))
t=200/55*h
t≈3.64 hours
answer:
x=-4/7 and the slope is 7
Answer:
∠RPQ = 27
Step-by-step explanation:
In ΔSRQ,
∠R = 90
∠SQR = 36°
∠R + ∠SQR + ∠RSQ = 180 {Angle sum property of triangle}
90 + 36 + ∠RSQ = 180
126 + ∠RSQ = 180
∠RSQ = 180 - 126
∠RSQ = 54°
∠PSQ +∠RSQ = 180 {Linear pair}
∠PSQ + 54 = 180
∠PSQ = 180 - 54
∠PSQ = 126
In ΔPSQ,
SQ = PS ,
So, ∠SQP = ∠SPQ {Angles opposite to equal sides are equal}
∠SQP = ∠SPQ =x
∠PSQ + x +x = 180 {Angle sum property of triangle}
126 + 2x = 180
2x = 180 - 126
2x = 54
x = 54/2
x = 27
∠RPQ = 27°
The value of AD in triangle ABC is approximately 9 cm.
BC = 6cm
Using trigonometric ratio for triangle CBD
sin 60° = opposite / hypotenuse
0.86602540378 = DC / 6
cross multiply
DC = 6 × 0.86602540378
DC = 5.19615242271
DC = 5.20 cm
Let's find side AD as follows:
tan 60° = AD / adjacent
AD = 5.20 × tan 60°
AD = 9.00666419936
AD ≈ 9 cm
learn more: brainly.com/question/10929357?referrer=searchResults
