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3 years ago

How many numbers are 3 units from 0 on the real numbers line

Mathematics

2 answers:

Fofino [41]3 years ago

7 0

Answer:

2 right? 3 and -3?

Step-by-step explanation:

Troyanec [42]3 years ago

7 0

Answer:

2 numbers

Step-by-step explanation:

● -3 and 3 are both 3 units apart from 0

We can find it with calculations.

You are moving in a real numbers line.

You can move either right or left.

You starting point is 0.

When you go 3 units to the right then you are adding 3.

● 3+0 = 3

When you go back 3 units starting from 0 then you are substracting 3.

● 0-3 = -3

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On a number line, which number is 7/9 of the way from -6 to 3

Paha777 [63]

Answer:

Step-by-step explanation:

if you go from -6 to 3 it is 9 spaces. so 7 spaces equals one.

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4 years ago

Which of the following coordinates would be on the line y = 2x (0, 2) (2, 0) (1, 2) (2, 2) Please explain it!

jolli1 [7]

Answ(0,2)

By putting x 0 and y 2

Step-by-step explanation:

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3 years ago

Daisy and Sam scored baskets at the basketball game in the ratio of 3:2. Daisy scored 6 more baskets than Sam. How many baskets

Scorpion4ik [409]

Daisy scored 15 baskets

5 0

3 years ago

HELP ME! @all smart people

larisa86 [58]

The first one is 5.3 you multiply 4x4 which is 16 then divide by 3 which then gives you the answer

6 0

3 years ago

Read 2 more answers

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

3 years ago