All categories

3 years ago

0.15 of 45....please help

Mathematics

1 answer:

slavikrds [6]3 years ago

8 0

.15= 15%
and 15 percent of 45 is 6.75

You might be interested in

The midpoint of AB is M(-5,1). If the coordinates of A are (-4,-5), what are the coordinates of B?

Elenna [48]

<u>ANSWER:</u>

The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)

<u>SOLUTION: </u>

Given, the midpoint of AB is M(-5,1).

The coordinates of A are (-4,-5),

We need to find the coordinates of B.

We know that, mid-point formula for two points A $(x_{1}, y_{1})$ and B $(x_{1}, y_{2})$ is given by

$M\left(x_{3}, y_{3}\right)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, in our problem, $\mathrm{x}_{3}=-5, \mathrm{y}_{3}=1, \mathrm{x}_{1}=-4 \text { and } \mathrm{y}_{1}=-5$

Now, on substituting values in midpoint formula, we get

$(-5,1)=\left(\frac{-4+x_{2}}{2}, \frac{-5+y_{2}}{2}\right)$

On comparing, with the formula,

$\frac{-4+x_{2}}{2}=-5 \text { and } \frac{-5+y_{2}}{2}=1$

$-4+\mathrm{x}_{2}=-10 \text { and }-5+\mathrm{y}_{2}=2$

$\mathrm{x}_{2}=-6 \text { and } \mathrm{y}_{2}=7$

Hence, the coordinates of b are (-6, 7).

5 0

3 years ago

Alicia answered 20 out of 25 problems correctly on a test. What percent did she get correct?

DedPeter [7]

80% of the problems correct.

3 0

2 years ago

Read 2 more answers

Give the domain and range.

Ymorist [56]

Answer:Graphs of inverse functions have a domain and range just like any other graph of a function. The domain of an inverse function is the range of the original, and the range of an inverse function is the domain of an original.

Step-by-step explanation:

7 0

3 years ago

It takes Betty 9 h to bake a cake and 8 h to knit a sweater. What is her opportunity cost of 1 cake in terms of knitted sweaters

trapecia [35]

Answer:78

Step-by-step explanation:

7 0

2 years ago

Plot the corresponding points for the inverse of the function represented by this table of values. x -4 0 3 7

NNADVOKAT [17]

Answer:

See explanation

Step-by-step explanation:

Given the function f(x) for which

$\begin{array}{ccccc}x&-4&0&3&7\\ \\f(x)&9&5&2&-2\end {array}$

If you want to plot the corresponding points for the inverse of the function f(x), change $f(x)$ into $y$ :

$\begin{array}{ccccc}x&-4&0&3&7\\ \\y&9&5&2&-2\end {array}$

switch x and y

$\begin{array}{ccccc}y&-4&0&3&7\\ \\x&9&5&2&-2\end {array}$

and then change $y$ into $f^{-1}(x).$

You get

$\begin{array}{ccccc}x&9&5&2&-2\\ \\f^{-1}(x)&-4&0&3&7\end {array}$

Now plot these points on the coordinate plane (see attached diagram).

3 0

2 years ago