Question

What is the solution to the system of equations below? x 3 y = 15 and 4 x 2 y = 30 (7 , 2) (2, 7) (4, 3) (3, 4).

Answer 1

Answer:

d

Step-by-step explanation:

Answer 2

The solution of the system of equation is x = 6 and y =3.

Given that

The system of the equation;

$\rm x+3y = 15\\\\4x+2y=20$

We have to find

The solution of the system of equation.

According to the question

The solution of the system of equation is determined in the following steps given below.

The system of the equation;

$\rm x+3y = 15\\\\4x+2y=20$

From equation 1,

$\rm x+3y = 15\\\\x = 15-3y$

Substitute the value of x in equation 2,

$\rm 4x+2y=30\\\\4(15-3y)+2y=30\\\\60-12y+2y=30\\\\-10y=30-60\\\\-10y=-30\\\\y = \dfrac{-30}{-10}\\\\y = 3$

Substitute the value of y in equation 1,

$\rm x +3y = 15\\\\x +3(3)=15\\\\x+9=15\\\\x =15-9\\\\x=6$

Hence, the solution of the system of equation is x = 6 and y =3.

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