II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
First you simplify both sides of the equation to make v+-41/9=-3/4.
Then add -41/9 to both sides to get the answer which is 137/36
v=137/36
Answer:ez 26
Step-by-step explanation: how do you not know this
Answer:
29
Step-by-step explanation:
Amplitude:4
Equation of Midline: 2
Period of function:3
Function shifted left:0.5
Function shifted up: 2
