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Mashutka [201]
3 years ago
14

A triangle has angles that measure 55°, 53°, and 72°. What kind of triangle is it? PLEASE BE QUICK!!

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Step-by-step explanation:

Sounds like a Scalene Triangle

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Graph the line with slope -3 passing through the point (1,5).
vitfil [10]
y = -3(1) + 5
aka Y= -3/1x + 5
6 0
4 years ago
Find the perimeter of quadrilateral ABCD with vertices A=(1,1) B=(4,4) C=(7,1) D=(4,-2). Explain your answer.​
Vanyuwa [196]

we have the coordinates of ABCD

there are 2 ways of doing this one is you find the distance of ab, bc, cd and da and then add the answers together. there is another way but i dont remember it properly so i am just gonna do it this way

distance between 2 point = \sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

AB

d = \sqrt {(4 - 1)^2 + (4 - 1)^2}

d = \sqrt {(3)^2 + (3)^2}

d = \sqrt {9 + 9}

d = \sqrt 18

AB = 4.24

now repeat the same with all

BC= 4.24

CD= 4.24

DA= 4.24

so its a square with all the same sides so perimeter is 4 x 4.24

perimeter is 16.96

hope this helps

mark me as brainliest please

3 0
3 years ago
(5x - 2y = 22<br> 8x - 2y = 28<br><br> Please!! Urgent
alexandr402 [8]

9514 1404 393

Answer:

  (x, y) = (2, -6)

Step-by-step explanation:

Subtract the first equation from the second.

  (8x -2y) -(5x -2y) = (28) -(22)

  3x = 6

  x = 2

Substitute this into either equation and solve for y.

  8(2) -2y = 28

  8 -y = 14 . . . . . . . . divide by 2

  y = 8 -14 = -6 . . . . add y-14 to both sides

The solution is (x, y) = (2, -6).

_____

I like a graphing calculator for a quick solution to such problems.

6 0
3 years ago
Please help me!!!!!!!
GrogVix [38]
4x^2 - 30 = 34
4x^2 = 34 + 30
4x^2 = 64
x^2 = 64/4
x^2 = 16
x = sqrt 16
x = -4 and 4......E and F

5 0
4 years ago
Consider the polynomials p(x) = 3x + 27x^2 and q(x)= 2 . Find the x -coordinate(s) of the point(s) of intersection of these two
Tom [10]

Answer:

The x -coordinate(s) of the point(s) of intersection of these two polynomials are x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333

The sum of these x -coordinates is \frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}

Step-by-step explanation:

The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).

Thus, 3x + 27x^2=2 and we solve for x

3x+27x^2-2=2-2\\27x^2+3x-2=0\\\left(27x^2-6x\right)+\left(9x-2\right)\\3x\left(9x-2\right)+\left(9x-2\right)\\\left(9x-2\right)\left(3x+1\right)=0

Using Zero Factor Theorem: = 0 if and only if = 0 or = 0

9x-2=0\\9x=2\\x=\frac{2}{9}

3x+1=0\\3x=-1\\x=-\frac{1}{3}

The solutions are:

x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333

The sum of these x -coordinates is

\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}

We can check our work with the graph of the two polynomials.

4 0
4 years ago
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