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Simora [160]
3 years ago
14

PLZZZ HELP WILL MARK BRAINLIEST IF RIGHT!

Mathematics
1 answer:
Finger [1]3 years ago
4 0

plug 88 into h and solve for t

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PLZ HELP ILL MARK BRANLEIST
DaniilM [7]

Answer:

I'm pretty positive it's (-4,-2)

Step-by-step explanation:

i looked at the grid

8 0
2 years ago
Please help me :'( I have been stuck on this
madam [21]

This is really weird.

-- NONE of the situations matches the equation at the top. 

-- And the equation at the top isn't even really any big deal . . .
it's <em>always</em> true, no matter what  ' t '  is .  If you remove all of
the parentheses and simplify it, it says that  6 = 6.  Well duh !

 
5 0
4 years ago
In this figure, sin(a) = 23
WITCHER [35]
a and b are complementary, or b=\dfrac\pi2-a. So

\cos b=\cos\left(\dfrac\pi2-a\right)=\sin a

and so \cos b=\dfrac23.
4 0
3 years ago
Chris labels every lattice point in the coordinate plane with the square of the distance from the point to the origin (a lattice
stiv31 [10]

Answer:

4 times

Step-by-step explanation:

A lattice point may be defined as the point of intersection of two grid lines or more than two grid lines that is placed in a regularly spaced points arrays. This is called a lattice point.

In the context, Chris tries to label every lattice point in a coordinate plane with its square of distance from the point to its origin. The lattice points means that the numbers are both the integers. So for number 25, Chris has to label 4 times

i.e. (55),(-5,5),(5,-5),(-5,-5)

4 0
3 years ago
Find the complex zeros of <br><img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%7Bx%7D%5E%7B3%20%7D%20%20-%2013%20%7Bx%7D%5
timama [110]

f(x) = 0 \\\\\implies x^3-13x^2+59x -87 =0\\\\\implies x^3 -3x^2 -10x^2 +30x +29x - 87=0\\\\\implies x^2(x-3)  - 10x(x-3) + 29(x-3) =0\\\\\implies (x-3)(x^2 -10x +29) =0\\\\\implies x - 3 = 0 ~~ \text{or}~~x^2 -10x +29 = 0\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{-(-10) \pm \sqrt{(-10)^2 -4 \cdot 1 \cdot 29}}{2(1)}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm \sqrt{-16}}{2}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm 4i }{2}\\

\\\implies x =3~~ \text{ or} ~~ x =5 \pm 2i\\\\\text{Hence the complex roots are,}~ 5- 2i ~~ \text{and} ~~5 + 2i

6 0
3 years ago
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