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3 years ago

13

How to write 3,24 as a common fraction without using a calculator

1 answer:

olya-2409 [2.1K]3 years ago

4 0

Answer:

dont trust me on this but i think it is 3/8

Step-by-step explanation:

You might be interested in

Which statement explains the lines 2x+y=4 and y=1/2x+4 are related

Inessa [10]

Answer:

The lines are perpendicular

Step-by-step explanation:

we have

$2x+y=4$

isolate the variable y

$y=-2x+4$ ----> equation A

The slope of the line A is $m=-2$

$y=\frac{1}{2}x+4$ -----> equation B

The slope of the line B is $m=\frac{1}{2}$

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

In this problem

The slopes of line A and line B are opposite reciprocal

therefore

The lines are perpendicular

4 0

3 years ago

Read 2 more answers

A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4

vlabodo [156]

Answer:

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

Step-by-step explanation:

Bernoulli's equation,

$P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2$

P₁ = P₂= atmospheric presser

$\rho$ = density

$\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2$ [since P₁ = P₂]

$\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)$

$\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2$

$\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2$

$\Rightarrow v^2_2- v^2_1=2g h$ [ $h_1-h_2=h$ ]

Here $v_1\approx 0$

$\Rightarrow v^2_2=2g h$

$\therefore v_2=\sqrt {2gh$

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole $v_2$ = $\sqrt {2\times 9.8\times 10.4}$ m/s

=14.28 m/s.

Given, the rate of flow from the leak is $2.53\times 10^{-3}$ $m^3/min$

$=\frac{2.53\times 10^{-3}}{60}$ $m^3/s$

Let the diameter of the hole be d.

Then the cross section area of the hole is $=\pi (\frac d2)^2$

We know that,

The rate of flow = Cross section area × speed

$\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28$

$\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}$

$\Rightarrow d= 1.94 \times 10^{-3}$

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

4 0

4 years ago

Find the difference.

RoseWind [281]

The correct answer is C.

8 0

3 years ago

Read 2 more answers

Alja [10]

Answer:

(-∞ , -1) ∪ (4 , ∞)

Step-by-step explanation:

-1 > 3x + 2 or 3x + 2 > 14

-1> 3x + 2 or 3x + 2 > 14

-1 - 2 > 3x or 3x > 14 - 2

-3 > 3x or 3x > 12

-1 > x or x > 4

(-∞ , -1) ∪ (4 , ∞)

Hope it helps :)

Please mark my answer as the brainliest

8 0

1 year ago

At 7:00 pm, the temperature was -7 °F. The next morning the temperature had raised

denis23 [38]

Answer:

49 degrees

Step-by-step explanation

5 0

3 years ago

Read 2 more answers