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Murljashka [212]
3 years ago
14

Write an equation in slope-intercept form of the line going through the points (-1,6)

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0

Answer:

Equation in slope-intercept form : y = -1x + 5

Step-by-step explanation:

Given points are:

(-1, 6) and (5,0)

We will first find the slope.

m = \frac{y_2-y_1}{x_2-x_1}\\\\m = \frac{0-6}{5-(-1)}\\\\m = \frac{-6}{6}\\m = -1

The general equation for slope intercept form is;

y = mx + b

Now we will find the value of b by putting one of the points in the general equation

Putting (5,0)

0 = -1(5) + b

0 = -5 + b

b = 5

The equation in slope intercept form is;

y = -1x + 5

Hence,

Equation in slope-intercept form : y = -1x + 5

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Answer:

p(x)=(x+1)(x+2)(x-3).

Step-by-step explanation:

Note: The given function is not correct.

Consider the given polynomial is

p(x)=x^3-7x-6

It is given that (x+1) is a factor of given function.

Using synthetic division, divide P(x) by (x+1) as shown below.

-1  |     1      0     -7      -6

    |           -1       1       6

--------------------------------------

        1       -1      -6       0

--------------------------------------

Bottom line represents the coefficients of quotient except the last element because it is remainder. So, the given function can be written as

p(x)=(x+1)(x^2-x-6)

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