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nikitadnepr [17]
3 years ago
5

The half life of a chemical element substance is 16 days, How long will it takes for the substance to decay from 120mg to 2 mg

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

94.5 days

Step-by-step explanation:

We are asked to calculate the time.

The formula to calculate the time for half life =

t = t½ × In (Nt/No)/-In2

t½ = half life = 16 days

No = Initial substance = 120mg

Nt = Amount of substances after time t = 2 mg

t = 16 × In (2/120)/-In2

t = 94.510249529736 days

Approximately = 94.5 days

Therefore, the time it would take for the substance to decay from 120mg to 2 mg is 94.5 days.

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What are the steps to solve for: 1/5(x+5)=1/4(x-3)+1
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\frac{x+5}{5} = \frac{1}{4} (x-3)+1

Step 2. Simplify \frac{x+5}{5} to 1+ \frac{x}{5}

1+ \frac{x}{5} = \frac{1}{4} (x-3)+1

Step 3. Simplify \frac{1}{4} (x-3) to \frac{x-3}{4}

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Step 4. Cancel 1 on both sides

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Step 5. Multiply both sides by 20 (the LCM of 5,4)

4x=5(x-3)

Step 6. Expand

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Step 7. Subtract 5x from both sides

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Step 8. Simplify 4x-5x to -x

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Done! :) Hope this helps! :)








3 0
3 years ago
Please help right now!!
Oksana_A [137]
i can’t see the question
8 0
3 years ago
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For the following geometric sequence, find the recursive formula.<br> {-80, 20, -5, ...}
skad [1K]
For the<span> geometric sequence, it has two forms of formula

</span>
<span>We are interested in the recursive formula now

</span>
<span> {-80, 20, -5, ...}

The common ratio is (20/-80)=(-5/20)=-1/4=-0.25

So our r</span><span>ecursive formula would bea_n=a_{n-1}*(-0.25)=a_{n-1}*(- \frac{1}{4} )


</span>

I hope that helps!



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3 years ago
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4 years ago
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