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evablogger [386]
2 years ago
9

A skateboarder is practicing in the city park. He is skating up and down the steepest straight-line ramp. If the highest point o

n the ramp is 30 feet above the ground and the horizontal distance from the base of the ramp to a point directly beneath the upper end is 500 feet, what is the slope of the ramp?
A)500/30
B)50/3
C)3/50
D) None of these
Mathematics
1 answer:
dalvyx [7]2 years ago
3 0
C is the answer to your problem have a good day
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Hello, please consider the following.

We will multiply the numerator and denominator by

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First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

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