2 years ago

Can someone please help me on this

Mathematics

1 answer:

Tanzania [10]2 years ago

7 0

$a=2(-2)-1 = -4-1 =-5\\\\b=2(-1)-1 = -2 - 1 = -3\\\\c=2(1)-1 = 2-1 = 1\\\\d=2(2) -1 = 4 -1 =3$

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Step-by-step explanation:

Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

$\binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{60}{3}=\frac{60!}{3!(60-3)!}\\\\\binom{60}{3}=\frac{60!}{3!(57)!}\\\\\binom{60}{3}=\frac{60*59*58}{3*2*1}\\ \\\binom{60}{3}=34220$