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erik [133]
3 years ago
6

(f o g) (x) =f(x) =x^2 - 2x , g(x) = x + 8x^2 ( x squared) ​

Mathematics
2 answers:
lana [24]3 years ago
3 0

Answer:x

2

(

x

s

q

u

a

r

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d

)

.

(

f

o

g

)

(

x

)

=

f

(

x

+

8

)

=

x

2

+

14

x

+

48

x

2

(

x

s

q

u

a

r

e

d

)

=

x

2

s

2

q

2

u

2

a

2

r

2

e

2

d

2

Step-by-step explanation:

Natali5045456 [20]3 years ago
3 0

Answer:

Step-by-step explanation:

(f∘g)(x) = f(g(x))

= f(x+8)

= (x+8)² - 2(x+8)

= (x²+16x+64) - (2x-16)

= (x²+16x+64) - 2x+16

= x² + 14x + 48

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A stew recipe calls for 3.75 pounds of meat. Jack wants to make 5 batches of stew. How many pounds of meat does he need?
suter [353]
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3 0
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Jlenok [28]

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7 0
3 years ago
Quick algebra 1 question for 50 points!
snow_tiger [21]

Answer:

Yes.

Step-by-step explanation:

Yes, the given line can be used to make reasonable predictions of the number of cheese pizzas that will be sold, since the scatter points clearly show a trend.

As time goes on, the number of pizzas sold is getting bigger, and the trend is what created the line.

The data was taken over 8 consecutive weeks, so we can assume that it can be used in our prediction.

Since the trend has been pretty consistent over periods of time, we can expect it to continue in the upcoming weeks.

3 0
1 year ago
The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. Sh
yulyashka [42]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 25235

For the alternative hypothesis,

µ > 25235

This is a right tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100,

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 27524

µ = population mean = 25235

s = samples standard deviation = 6000

t = (27524 - 25235)/(6000/√100) = 3.815

We would determine the p value using the t test calculator. It becomes

p = 0.000119

Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.

6 0
2 years ago
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