120 - 4 - 6 = ( that is the process, you ca find the answer)
2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.
Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.
Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.
Answer:
45°
Step-by-step explanation:
I think you meant m<ACB, and from what I see here, I took half of 90°, which is 45°.
The value of cos x⁰ from the information given is; g/h.
<h3>What is the value of cos x⁰?</h3>
According to the task content;
- The value of cos x° from the information contained in the task content is required.
From conventional Trigonometry;
- It follows that tan x = sin x/cos x.
On this note, it follows that;
cos x⁰ = sin x⁰/tan x⁰.
cos x⁰ = 6/h ÷ 6/g
cos x⁰ = g/h
Ultimately, the value of Cos x⁰ by evaluation is g/h.
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33 years old would be correct