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2 years ago

12

Calvin earned $1,425 dollars by working five days in a week . He also received a bonus of $200.What is the average amount that h

e eared per day

1 answer:

DENIUS [597]2 years ago

3 0

Answer: Average amount that he earned per day =$325

Explanation:

Amount Calvin earned by working five days in a week = $1425

Amount he received a bonus = $200

Total amount earned in a five days is given by

$= \$1425+\$200\\=\$1625$

Average amount that he earned per day $=\frac{ \text{Sum of observation}}{\text{Total number of observation}}$

So, Average amount that he earned per day is given by

$=\frac{1625}{5}\\=\$325$

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The function $f(x) = \frac{x^{2}-4\cdot x}{x^{2}-16}$ has the following set of solutions:

$f(4.1) = 0.506173$ , $f(4.05) = 0.503106$ , $f(4.01) = 0.500624$ , $f(4.001) = 0.500062$ , $f(4.0001) = 0.500006$ , $f(4.0001) = 0.500006$

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Step-by-step explanation:

Let be $f(x) = \frac{x^{2}-4\cdot x}{x^{2}-16}$ , we proceed to simplify the expression by Algebraic means:

1) $\frac{x^{2}-4\cdot x}{x^{2}-16}$ Given

2) $\frac{x\cdot (x-4)}{(x-4)\cdot (x+4)}$ Associative, commutative and distributive properties/ $a^{2}-b^{2} = (a+b)\cdot (a - b)$

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Now we evaluate the function for each value:

$x = 4.1$

$f(4.1) = \frac{4.1}{4.1+4}$

$f(4.1) = 0.506173$

$x = 4.05$

$f(4.05) = \frac{4.05}{4.05 + 4}$

$f(4.05) = 0.503106$

$x = 4.01$

$f(4.01) = \frac{4.01}{4.01 + 4}$

$f(4.01) = 0.500624$

$x = 4.001$

$f(4.001) = \frac{4.001}{4.001+4}$

$f(4.001) = 0.500062$

$x = 4.0001$

$f(4.0001) = \frac{4.0001}{4.0001 + 4}$

$f(4.0001) = 0.500006$

$x = 3.9$

$f(3.9) = \frac{3.9}{3.9+4}$

$f(3.9) = 0.493671$

$x = 3.95$

$f(3.95) = \frac{3.95}{3.95+4}$

$f(3.95) = 0.496855$

$x = 3.99$

$f(3.99) = \frac{3.99}{3.99+4}$

$f(3.99) = 0.499374$

$x = 3.999$

$f(3.999) = \frac{3.999}{3.999 + 4}$

$f(3.999) = 0.499937$

$x = 3.9999$

$f(3.9999) = \frac{3.9999}{3.9999 + 4}$

$f(3.9999) = 0.499994$

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