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3 years ago

I don’t get this sum 1 plz help quickkk

Mathematics

2 answers:

Inessa05 [86]3 years ago

8 0

Answer:

I would say A

Step-by-step explanation:

sattari [20]3 years ago

5 0

Answer:

that would be -9 since it's an isosceles triangle, which two base angles are the same, so that would add to 100. substitute -9 for x and add them to get 80. add all the angles and you get 180.

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Write an equivalent expression for (2 m + 3) (m - 1)

Dmitry [639]

Answer:

$2m^2-3m-9$

Step-by-step explanation:

use FOIL

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$2m^2-6m+3m-9\\\\-6m+3m=-3m\\\\2m^2-3m-9$

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3 years ago

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stiv31 [10]

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3 years ago

1. Find the sum of csc230° and cot2 45°.

wlad13 [49]

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6 0

3 years ago

Please help me in answers 6 and 8

Ivenika [448]

For #6

x + y = -10
x - y = 2

First solve for y in one of the equations

x - y = 2
-y = 2 - x
y = -2 + x
y = x - 2

Now substitute into one of the equations and solve for x

x + y = -10
x + x - 2 = -10
2x - 2 = -10
2x = -8
x = -4

3 0

3 years ago

Any help? Much appreciated

natulia [17]

Answer:

$\frac{6+\sqrt{27} }{4-\sqrt{3} } = \frac{r+s\sqrt{3} }{13} \\We\ may\ multiply\ the\ numerator\ and\ denominator\ with\ (4+\sqrt{3} ).\\Hence,\\\frac{(6+\sqrt{27})(4+\sqrt{3}) }{13} = \frac{r+s\sqrt{3} }{13} \\Hence,\\24+6\sqrt{3} +4\sqrt{27} +9= r+s\sqrt{3}\\24+6\sqrt{3} +4*3\sqrt{3} } +9= r+s\sqrt{3}\\24+6\sqrt{3} +12\sqrt{3}+9 = r+s\sqrt{3}\\33+18\sqrt{3} = r+s\sqrt{3}\\Hence,\\r=33, s=18$

5 0

3 years ago