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Tems11 [23]
3 years ago
10

The temperature is below 2 degrees Fahrenheit.

Mathematics
2 answers:
horrorfan [7]3 years ago
7 0

Answer:

A number line going from 0 to 3. An open circle is at 2. Everything to the left of the circle is shaded.

Step-by-step explanation:

First, remember that when an endpoint is not in the solution set, we graph an open circle. While if the endpoint is in the solution set, we graph it with a closed circle.

For example, in:

x > 2

x = 2 is not a solution, then we will have an open circle at x = 2

While in the case of:

x ≥ 2

x = 2 is a possible solution, then we graph with a closed circle.

Ok, in this case we have:

t < 2

t is strictly smaller than 2, and t = 2 is not a solution.

Then:

we will have an open circle at 2, and we need to shade all the values to the left of 2 (the values smaller than 2)

The correct option is:

A number line going from 0 to 3. An open circle is at 2. Everything to the left of the circle is shaded.

Anna007 [38]3 years ago
3 0

Answer:

the middle one.

Step-by-step explanation:

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Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u><u> </u><u>and</u><u> </u><u>c</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

Step-by-step explanation:

• Let's first phrase out the general equation of a line

{ \rm{y = mx + c}}

  • m is the slope
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[ remember that a general line equation must be in slope - intercept form as shown above ]

• from our question, we are given the equation;

{ \rm{3y + 6x =  - 3}}

• let's make y the subject in order to make the equation in slope - intercept format.

→ <em>r</em><em>e</em><em>m</em><em>e</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>a</em><em>p</em><em>p</em><em>l</em><em>y</em><em> </em><em>"</em><em>s</em><em>u</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>m</em><em>a</em><em>k</em><em>i</em><em>n</em><em>g</em><em> </em><em>k</em><em>n</em><em>o</em><em>w</em><em>l</em><em>e</em><em>d</em><em>g</em><em>e</em><em>"</em>

{ \rm{3y =  - 3 - 6x}} \\  \\ { \rm{3y =  - 6x - 3}} \\  \\ { \rm{ \frac{3y}{3}  =  \frac{ - 6x}{3}  -  \frac{3}{3} }} \\  \\  { \boxed{ \rm{y =  - 2x - 1}}}

• The above boxed equation is now a general equation. Let's extract out slope, m and y-intercept, c

{ \rm{m \:  \dashrightarrow \:  - 2}} \\  \\ { \rm{c \:  \dashrightarrow \:  - 1}}

8 0
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