Im pretty sure its
(6, 0)
(0, –30)
I could be wrong though..
Question isn't clearly stated.
The. Probability o
Answer:
Step-by-step explanation:
How many times must you roll an ordinary 6-sided dice for the probability of getting at least one multiple of 3 more than 0.7
Given a six sided die : (1, 2, 3, 4, 5, 6)
Multiple of 3 = (3, 6) = 2
Getting a multiple of 3 on a single roll :
P(multiple of 3) = 2 / 6 = 1/3
You need to look at this as a proportion and ratio.
If
![\frac{9}{180}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7B180%7D%20)
seventh graders were chosen, that is
![\frac{1}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B20%7D%20)
of them.
You need to find
![\frac{1}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B20%7D%20)
of the sixth graders to remain constant.
![\frac{1}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B20%7D%20)
of 160 = 8 students.
9+×(5)=7 and thats ur answer. more than equals to adding and five is there just to be there so just multiply it in parentheses