Answer:
64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
Step-by-step explanation:
Volume of cylinder = V
Radius of cylinder = r = 0.5 m
Height of the cylinder = 5 m
Volume of cylinder = 
Mass of gasoline = m
Density of gasoline = d = 
Work done to pump the gasoline out of the tank W
Acceleration due to gravity = g 
The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m
64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
Answer:
the answer is c hope u get it right
Step-by-step explanation:
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Since we are shifting equation up 3 units, the equation would be y=x+3
X=10
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To solve this, you need to isolate/get the variable "u" by itself in the inequality: u = unknown number
2u - 3 < 1 Add 3 on both sides
2u - 3 + 3 < 1 + 3
2u < 4 Divide 2 on both sides to get "u" by itself
u < 2 (u is any number less than 2)
When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.
When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.
u < 2
Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.
