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2 years ago

Who's over 17 and tryna talk

Mathematics

1 answer:

kow [346]2 years ago

6 0

Answer:

walang keef fuzzy gasification

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Given the function f(x) = 2|x + 6| – 4, for what values of x is f(x) = 6?

statuscvo [17]

Given two functions, we can combine them in such a way so that the outputs of one function become the inputs of the other. ... 3, right parenthesis first and then substitute that result into f f ff to find our answer. ..... Problem 1 ..... end{aligned} (h∘g)(x)=h(g(x))=(g(x))2−2(g(x))=(x+4)2−2(x+4)=x2+8x+16−2x−8=x2+6x+8Define.

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2 years ago

-8+y=14

Sati [7]

Answer:

y = 22

Step-by-step explanation:

we want to move the -8 to the other side, so 14+8 = 22

y = 22

check: -8 + 22 = 14

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2 years ago

Read 2 more answers

find the surface areas of the larger cone and the smaller cone in terms of pi. compare the surface areas using a percent. (the m

serious [3.7K]

ANSWER :

Surface area of larger cone : 24π units^2

Surface area of smaller cone : 6π units^2

The surface area of the smaller cone is 25% of that of the larger cone.

EXPLANATION :

From the given problem,

AB = 3 is the radius of the larger cone and the slanted height is BC = 5

DE = 1.5 is the radius of the smaller cone and the slanted height is EC = 2.5

Recall the surface area of the cone :

$A=\pi r^2+\pi rL$

where r = radius and L = slanted height.

For the larger cone, r = 3 and L = 5

$\begin{gathered} A=\pi(3)^2+\pi(3)(5) \\ A=24\pi \end{gathered}$

For the smaller cone, r = 1.5 and L = 2.5

$\begin{gathered} A=\pi(1.5)^2+\pi(1.5)(2.5) \\ A=6\pi \end{gathered}$

Comparing the surface areas :

The area of the smaller cone compared to the larger cone is :

$\begin{gathered} \frac{smaller}{larger}\times100=\frac{6\pi}{24\pi}\times100 \\ \\ =25\% \end{gathered}$

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10 months ago

Which of the following pairs of triangles are similar?

Ganezh [65]

The second and the fourth

6 0

2 years ago

Combine the following fractions by addition or subtraction as directed.

Marina86 [1]

Answer: $\frac{6}{y^2-xy}-\frac{6}{x^2-xy}=\frac{6(x+y)}{xy(y-x)}$

Explanation:

Combining the fractions, we have:

$\begin{gathered} \frac{6(x^2-xy)-6(y^2-xy)}{(x^2-xy)(y^2-xy)} \\ \\ =\frac{6x^2-6xy-6y^2+6xy}{(x^2-xy)(y^2-xy)} \\ \\ =\frac{6x^2-6y^2}{x(x-y).y(y-x)} \\ \\ =\frac{6(x-y)(x+y)}{-xy(x-y)^2} \\ \\ =\frac{-6(x+y)}{xy(x-y)} \\ \\ =\frac{6(x+y)}{xy(y-x)} \end{gathered}$

8 0

1 year ago