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oksano4ka [1.4K]
3 years ago
9

Who's over 17 and tryna talk

Mathematics
1 answer:
kow [346]3 years ago
6 0

Answer:

walang keef fuzzy gasification

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Find the maximum value of y = -x^2 + 6x + 5​
Firdavs [7]
The answer is C, you use the formula x=-b/2a
7 0
3 years ago
Read 2 more answers
Question
Ahat [919]

Answer:

4 minutes.

Step-by-step explanation:

There are three trains that Rachel has to take to go to her job. The total time is taken by her, on average, 1 hour and 20 minutes i.e. (60 + 20) = 80 minutes.

In his journey, she walks for 15 minutes and a train journey for about 53 minutes.

Then the total waiting time for the trains is (80 - 53 - 15) = 12 minutes.

Therefore, the average waiting time, in minutes, at each of the three train stations will be \frac{12}{3} = 4 minutes. (Answer)

8 0
4 years ago
Find the scale factor of the dilation ​
Reil [10]

Answer:

k=1/2

It is a reduction

Step-by-step explanation:

To the scale factor, you simply divide the length of the post image by the image.

10/20=k

1/2=k

5 0
3 years ago
In the year 2000, the average cost of a computer could be modeled by the equation C = -5t2 + 750, where t is the number of years
elena55 [62]

Answer:

\Delta C=-5t^2-250

Step-by-step explanation:

Given:

The average cost of a computer in the year 2000 is given as:

C=-5t^2+750

The average cost of a computer in the year 2008 is given as:

C=-10t^2+500

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.

Framing in equation form, we get:

Difference in average cost (ΔC) is given as:

\Delta C=C_{2008}-C_{2000}\\\\\Delta C= (-10t^2+500)-(-5t^2+750)\\\\\textrm{Distributing the megative sign inside the second polynomial, we get:}\\\\\Delta C=-10t^2+500+5t^2-750\\\\\textrm{Grouping like terms, we get}\\\\\Delta C=(-10t^2+5t^2)+(500-750)\\\\\Delta C=-5t^2-250

Therefore, the difference in the costs for a computer between 2008 and 2000 is \Delta C=-5t^2-250

7 0
4 years ago
A system of equations is shown:
Harrizon [31]

Answer:

<h2>(1, 4)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}2x=-y+6&(1)\\-4x+3y=8&(2)\end{array}\right\\\\(1)\\-y+6=2x\qquad\text{subtract 6 from both sides}\\-y=2x-6\qquad\text{change the signs}\\y=6-2x\\\\\text{substitute it to (2):}\\\\(2)\\-4x+3(6-2x)=8\qquad\text{use the distributive property}\\-4x+(3)(6)+(3)(-2x)=8\\-4x+18-6x=8\qquad\text{subtract 18 from both sides}\\-10x=-10\qquad\text{divide both sides by (-10)}\\x=1\\\\\text{put the value of x to (1):}\\\\y=6-2(1)\\y=6-2\\y=4

6 0
3 years ago
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