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ad-work [718]
3 years ago
13

Please help! I can't seem to figure this stuff out...

Mathematics
1 answer:
Fudgin [204]3 years ago
8 0
1: always rearrange the equation to y = mx + c so....
x - y = o

x = y

So the gradient is 1 and it intersects the y axis at (0,0)

The three points could be (1,1), (2,2), (3,3) and so on



2: -x -2y = -10
Multiply everything by -1

x + 2y = 10

2y = 10 - x

y = 5 - x/2

The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on



3: x + y = -2

y = -2 - x

The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on



4: -3y =-x -7

Multiply everything by -1

3y = x + 7

y = x/3 + 7/3

The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o



5: -y = -x + 1

y = x - 1

The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on


Hope this helps! Any questions let me know :)
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Cup A

<em><u>Formula</u></em>

V = 1/3 pi r^2 h

<em><u>Givens</u></em>

r = d/2 = 2/2 = 1 inch

pi = 3.14

h = 4 inches

<em><u>Solution</u></em>

V = 1/3 * 3.14 * 1^2 * 4

V = 4.187

Cup B

<em><u>Formula</u></em>

V = pi * r^2 * h

<em><u>Givens</u></em>

pi = 3.14

r = d/2 = 2/2 = 1

h = 6

<em><u>Solution</u></em>

V = pi * r^2 * h

V = 3.14 * 1^2 * 6

V = 18.84

<em><u>Answer</u></em>

VB - VA = 18.84 cu in - 4.187 = 14.65 = 14.7 Rounded.

Answer C

4 0
3 years ago
For the right triangles below, find the exact values of the side lengths and .
konstantin123 [22]

Answer:

c=\frac{2\sqrt{3}}{3}

h=3\sqrt{2}

Step-by-step explanation:

Please see the attached image. It is a good idea it to memorize these triangle properties because you will definitely use them in the future.

c=\frac{2}{\sqrt{3} } =\frac{2*\sqrt{3} }{\sqrt{3} *\sqrt{3} } =\frac{2\sqrt{3}}{3}

h=3\sqrt{2}

5 0
3 years ago
Put the numbers in order from least to greatest :
motikmotik
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If X^2= 3+2√2 what is the value of √x+1/√x
Nikolay [14]

Step-by-step explanation:

Let √x - 1/√x = a

Squaring both the sides,

x + 1/x - 2 = a^2

Putting the value,

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a^2 = 1 - 2√2 + 1/(3–2√2)

= [(3–2√2) (1–2√2) + 1] / 3–2√2

= {3 - 8√2 + 9} / 3–2√2

= [12 - 8√2] / 3–2√2

Rationalising both the sides

= {(12 - 8√2)(3+2√2)} ÷ (9–8)

= 36 + 24√2 - 24√2 + 16(2)

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=> 4

a^2 = 4

a = √4

a = 2, -2

So,

√x - 1/√x = a = 2, -2.

5 0
3 years ago
Let U be the set of whole numbers from 5-10 inclusive. Set A= {5, 7, 9}, Set B = {5, 8, 10}. AU~B &lt;---------
pav-90 [236]

Answer:

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Let U be the set of whole numbers from 5-10 inclusive. Set A={5, 7, 9 ...

6 0
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