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ddd [48]
3 years ago
13

Which shows the location of the point (2,-5) after being reflected across the y-axis?

Mathematics
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:

Where is the graph my friend??

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Step-by-step explanation:

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Step-by-step explanation:

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0.4444444 into a fraction
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Step 1: Write down the decimal divided by 1. 
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Which function equation is represented by the graph?<br> PLEASE HELP
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Read 2 more answers
Which of the following integrals represents the volume of the solid obtained by rotating the region bounded by the curves y = (x
Troyanec [42]

Answer:

\displaystyle V = \pi \int _0^{16}\left[10-\left(\frac{1}{8}y-2\right)\right] ^2 - \left[10 - \left(2+y^{{}^{1}\!/\!{}_{4}}\right)\right]^2\, dy

Step-by-step explanation:

We want to find the volume of the solid obtained by rotating the region between the two curves:

y=(x-2)^4\text{ and } 8x-y=16

About the line <em>x</em> = 16.

Since our axis of revolution is vertical, we can use the washer method in terms of <em>y</em>.

\displaystyle V = \pi \int _c^d[R(y)]^2 -[r(y)}]^2\, dy

Where R(y) is the outer radius and r(y) is the inner radius.

First, solve each equation in terms of <em>y: </em>

<em />\displaystyle x_1 = \frac{1}{8}y+2\text{ and }  x_2 = y^{{}^{1}\! /\! {}_{4}}+2<em />

<em />

From the diagram below, we can see that the outer radius R(y) is (10 - <em>x</em>₁) and that the inner radius r(y) is (10 - <em>x</em>₂). The limits of integration will be from <em>y</em> = 0 to <em>y</em> = 16. Substitute:

\displaystyle V = \pi \int_0^{16}\left[\underbrace{10-\left(\frac{1}{8}y+2\right)}_{R(y)}\right]^2 - \left[\underbrace{10-\left(y^{{}^{1}\!/\!{}_{4}}+2\right)}_{r(y)}\right]^2\, dy

Thus, our volume is:

\displaystyle V = \pi \int _0^{16}\left[10-\left(\frac{1}{8}y-2\right)\right] ^2 - \left[10 - \left(2+y^{{}^{1}\!/\!{}_{4}}\right)\right]^2\, dy

*I labeled the diagram incorrectly. Let R(x) be R(y) and r(x) be r(y).

6 0
3 years ago
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