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3 years ago

Match each situation with a diagram

Mathematics

1 answer:

Evgen [1.6K]3 years ago

8 0

Match 1 with B
Match 2 with A
Match 3 with C

Explanation:

Uhhh just multiply the X by the fraction to get both amounts. (x is 4 in these cases)

Hope this helps

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How do you get the answer

lilavasa [31]

Answer:

(x + 2)(x - 4)

Step-by-step explanation:

Given the zeros of a function, say x = a and x = b, then

the factors are (x - a) and (x - b)

From the graph

The zeros are x = - 2 and x = 4, thus the factors are

(x - (- 2)) and (x - 4), that is (x + 2) and (x - 4)

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3 years ago

Kirk traded New Zealand dollars for Mexican pesos at an exchange rate of 1 New Zealand dollar = 8.8352 Mexican pesos. He gave th

In-s [12.5K]

The Correct Answer is. 22,397.23

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3 years ago

How many milliliters of water are in a 2- liter bottle of water

e-lub [12.9K]

There are 1000 milliliters per liter. So there are 2,000 milliliters in 2 liters

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3 years ago

In a certain chemical reaction, a substance is converted into another substance at a rate proportional to the square of the amou

morpeh [17]

Answer:

$Q (t) = \frac{90}{7t +2 }$

$Q(2) = 5.63 \ g$

Step-by-step explanation:

Let Q(t) be the first substance at time t. We know that the rate of change is directly proportional to $Q^2$ .

Hence we can write it as:

$\frac{dQ}{dt} \propto Q^2\\\\\frac{dQ}{dt} = kQ^2$

Step 1: Integrating the function to form an equation:

$\frac{dQ}{dt} = kQ^2\\\\\frac{dQ}{Q^2} = k \ dt\\\\\int \frac{dQ}{Q^2} = \int k \ dt\\\\- \frac{1}{Q} = kt + C$ ----------------------------------------------- equation (1)

Step 2: Substitute the value Q(0) = 45 in equation 1 to find value of C.

$-\frac{1}{Q} = kt + C\\\\-\frac{1}{45} = k(0) + C\\\\-\frac{1}{45} = C\\\\\\-\frac{1}{Q} = kt - \frac{1}{45}\\$ ---------------------------------------------- equation (2)

Step 3: Substitute the value Q(1) = 10 in equation 2 to find the value of k.

$-\frac{1}{Q} = kt - \frac{1}{45}\\\\-\frac{1}{10} = k(1) - \frac{1}{45}\\\\-\frac{1}{10} - \frac{1}{45} = k \\\\\frac{2-9}{90} = k\\\\-\frac{7}{90} = k$

Step 4: Form the equation and simplify it.

$-\frac{1}{Q} = -\frac{7}{90} t - \frac{1}{45}\\ \\\frac{1}{Q} = \frac{7}{90}t + \frac{2}{90}\\\\\frac{1}{Q} = \frac{7t + 2}{90}\\\\\\\bullet \ cross - multiply \ the \ equation \\\\Q = \frac{90}{7t + 2}$

Step 5: To find the amount of substance after 2 hours, we substitute the value of t with 2.

$Q = \frac{90}{7t + 2}\\\\Q = \frac{90}{7(2) + 2}\\\\Q = \frac{90}{14+ 2}\\\\Q = \frac{90}{16}\\\\Q = 5.625 \approx 5.63$

The amount of substance after 2 hours is 5.63 grams.

5 0

3 years ago

Find the horizontal asymptote for y= 5x/x+6 . y = 0 y = −6 none y = 5

gayaneshka [121]

Answer:

Find where the expression

is undefined.

−

Consider the rational function

(

)

where

is the degree of the numerator and

is the degree of the denominator.

1. If

, then the x-axis,

, is the horizontal asymptote.

2. If

, then the horizontal asymptote is the line

3. If

, then there is no horizontal asymptote (there is an oblique asymptote).

Find

and

Since

, the horizontal asymptote is the line

where

and

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:

−

Horizontal Asymptotes:

No Oblique Asymptotes

image of graph

5 0

2 years ago

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