Answer:
y=-7/4x+5
Step-by-step explanation:
The line contains points at (4,-2) and (0,-5)
(y1-y2) / (x1-x2) = slope
(4,-2) =(x1,y1)
(0,-5) = (x2,y2)
(-2-5) / (4-0)
-7 / 4 = -7/4
y= -7/4x + b
plug in points for x and y to find b
-2=-7/4(4)+b
-2=-7+b
5=b
y=-7/4x+5
Answer:
Pretend that H is the midpoint of AB, connect O and H
=> OH is the median of ΔOAB
Since we know that OA = OB => ΔOAB is an isosceles triangle
=> OH is also the height of ΔOAB
=> ∠OBA = ∠OAB = (180° - ∠AOB)/2 = (180° - 120°)/2 = 60°/2 = 30°
Now look at ΔOHB (that you create by connecting O and H)
We have:
cos30° = BH/OB
=> BH = cos30° · OB = √3/2 · x = (√3 x)/2
Because we have H as the midpoint of AB, we know that:
AB = 2 · BH = 2 · (√3 x)/2 = √3 x
So the answer is B
Answer:
See Below.
Step-by-step explanation:
We want to verify:
We will utilize the following identities:
And:
So, by substitution, we acquire:
Distribute:
The first and third term will cancel:
Combine like terms:
4^2*4^-3
16- .016 (taken from a fraction into a decimal and rounded to the nearest tenth)
16.984 is your answer.
I hope this helped you!
Answer:
294
Step-by-step explanation:
since the area is 7^3, the cube's side length is 7
SA = 6*7^2 = 294
