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3 years ago

NEED DONE BY 8 PLEASE HELP!!

Mathematics

1 answer:

iogann1982 [59]3 years ago

7 0

Answer:

a. 8 y/s; divide 40(distance) by 5(time)

b. 1/8 2/16 3/24 4/32 5/40 6/48 7/56; multiply speed and time ex. 8×1=8; 8×2=16; 8×3=24 and so on

c. 80 yards; multiply time and distance 8×10

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

Distribute 2 (9x^2 + 3).

beks73 [17]

Answer:

18x^2+6

Step-by-step explanation:

2(9x^2+3)

multiply each term in parentheses by 2

2 x 9x^2+2 x 3

calculate product

18x^2+2 x 3

multiply numbers

18x^2+6

5 0

2 years ago

Bonnie is making a dipping sauce. She mixes 150 milliliters of soy sauce with 100 milliliters of vinegar. How much soy sauce doe

oksian1 [2.3K]

Answer:

Bonnie is mixing 1.50 milliliter of soy sauce with 1 milliliter of vinegar

Step-by-step explanation:

Given

Bonnie mixes 150 milliliters of soy sauce with 100 milliliters of vinegar

So, in order to find the amount of soy sauce mixed with one ml of vinegar, we have to divide the amount of soy sauce by vinegar.

So,

$Soy\ sauce\ mixed\ with\ 1\ ml\ of\ vinegar\ =\frac{150}{100}\\ = \frac{3}{2}\\=1.50$

Hence,

Bonnie is mixing 1.50 milliliter of soy sauce with 1 milliliter of vinegar

3 0

3 years ago

Last week, Leon bought 8 pizzas and 13 cakes

romanna [79]

P = pizza and c =cakes

Last week: 8p + 13c = 134
Today: 28p + 4c = 220

Let’s take the formula for today and subtract 28p from each side to isolate the 4c.

4c = 220 - 28p

Now divide each side by 4

c = (220 - 28p)/4
Simplify to c = 55 - 7p

Now go to the formula for last week, substitute the c for 55-7p

8p + 13(55 - 7p) = 134
8p + 715 - 91p = 134

Simplify to 715 - 83p = 134

Let’s add 83p to each side.

715 = 134 + 83p

Subtract 134 from each side

581 = 83p

Divide each side by 83

p = $7

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2 years ago

Given a possible triangle ABC with a=5, b=11, and A=23 degrees, find a possible value for angle b. Round to the nearest tenth.

Stels [109]

<span>b. Round to the nearest tenth. please mark brainly</span>

6 0

3 years ago