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Rashid [163]
3 years ago
13

In 10 words or fewer, what other numbers do you think are in the domain of this function?​

Mathematics
1 answer:
Maru [420]3 years ago
5 0

Answer:

Numbers greater than or equal to 0.

Step-by-step explanation:

The domain of this function is {x∈R | x≥0}, meaning that x can be anything greater than or equal to 0.

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Pls help if you actually can
Setler79 [48]

The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

<h3>How to identify similar triangles?</h3>

From the image attached, we see that we are given the Parallelogram GRPC. Thus;

A.  The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;

∠CGB ≅ ∠PEB  (Alternate Interior Angles)

∠BPE ≅ ∠BCG  (Alternate Interior Angles)

∠GBC ≅ ∠EBP  (Vertical Angles)

C.  To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;

225/325 = PE/375  

PE = 260 ft

BE/425 = 225/325  

BE = 294 ft

Read more about Similar Triangles at; brainly.com/question/14285697

#SPJ1

5 0
1 year ago
If there are 1/2 cup of almonds how many more would you need for a third
irga5000 [103]
1/6 of almonds. you multiply the two numbers together.
5 0
3 years ago
(03.01 LC)
Sedaia [141]
  • Perpendicular=P=4
  • Base=B=4

Hypotenuse be H

Apply Pythagorean theorem

\\ \tt\hookrightarrow H^2=P^2+B^2

\\ \tt\hookrightarrow H^2=4^2+4^2

\\ \tt\hookrightarrow H^2=32

\\ \tt\hookrightarrow H=\sqrt{32}

\\ \tt\hookrightarrow H=5.8units

8 0
2 years ago
Describe the diffrence between algebraic expressions and numerical expressions
xxTIMURxx [149]
A numerical expression contains numbers and operations. An algebraic expression is almost exactly the same except it also contains variables.

6 0
3 years ago
G. Write the equation of the line in slope-intercept form.
Neko [114]

Answer:

  • y= x-2
  • y = 4/5 x+39/5

Step-by-step explanation:

1.

(3,1) and\:perpendicular \:to \: y = -x+1\\(3,1) = (x,y)\\m = -1\\In\: perpendicularism ; m_2 = \frac{-1}{m_1} \\m_2 = \frac{-1}{-1} \\m_2 =1\\y = mx+c\\1 = 1(3) +c\\1=3+c\\1-3=c\\-2 =c\\Substitute \:new \:values\:into\\y =mx+c\\y = 1x -2\\y = x-2

2.

(-1,7) =(x_1,y_1)\\\\5y = 4x+5\\\\Write\:in\:y=mx+c\:form\\\frac{5y}{5} = \frac{4}{5} x + \frac{5}{5} \\y = \frac{4}{5} x +1\\m = \frac{4}{5} \\\\y -y_1=m(x-x_1)\\y-7=\frac{4}{5} (x -(-1)\\y -7 = 4/5(x+1)\\y -7 = 4/5x +4/5\\\\y = \frac{4}{5} x+\frac{4}{5} +7\\\\y = \frac{4}{5} x +39/5

6 0
3 years ago
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