Use the vertical line test to determine whether the relation graphed is a function.

SBC is an isosceles triangle with main vertex S.

stira [4]

Answer + Step-by-step explanation:

1) D be the symmetric of B with respect to C then CD = BC

A the symmetric of C with respect to B then AB = BC

We obtain :

CD = BC

AB = BC

Then AB = CD

2) m∠SBA = 180 - SBC = 180 - SCB = m∠SCD

3) we have :

BA = CD

BS = CS

m∠SBA = m∠SCD

Then

the triangles SBA and SCD are congruent

4)

the triangles SBA and SCD are congruent Then SA = SD

Therefore SAD is an isosceles triangle.

4 0

2 years ago

12 + 2(x + 6) - 8 = 26

Kisachek [45]

Answer: x=5

Step-by-step e

6 0

3 years ago

Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th

Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 21-1 = 20$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have $T = 2.528$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{0.40}{\sqrt{21}} = 0.0873$

Now, we multiply T and s

$M = 2.528*0.0873 = 0.2207$

Then

The lower end of the interval is the mean subtracted by M. So:

$L = 3.27 - 0.2207 = 3.0493$

The upper end of the interval is the mean added to M. So:

$LCL = 3.27 + 0.2207 = 3.4907$

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0

3 years ago

Please help with 4-9!!!

olya-2409 [2.1K]

sdfsdf

4) $\frac{3m+15}{2} = 22.5$

Multiply by 2 on both sides

3m + 15 = 45

Subtract both sides by 15

3m = 30

Divide both sides by 3

so m = 3

5) $21= \frac{q+35}{8}$

Multiply both sides by 8

168 = q + 35

Subtract both sides by 35

q = 133

6) $14 + \frac{4z}{-11} = 66$

Subtract 14 from both sides

$\frac{4z}{-11} = 52$

multiply by -11 on both sides

4x = 572

Divide both sides by 4

x= 143

7) $\frac{3}{5} c - 6 = 9$

Add 6 on both sides

$\frac{3}{5} c = 15$

Multiply both sides by 5

3c = 75

Divide both sides by 3

c = 25

8) $\frac{t}{-2} + 17 = -9$

Subtract both sides by 17

$\frac{t}{-2} =26$

Multiply both sides by -2

t = -52

9) $-6 = \frac{5p-(-2)}{-7}$

Multiply both sides by -7

42= 5p + 2

subtract 2 from both sides

40 = 5p

Divide both sides by 5

so p = 8

6 0

3 years ago

Read 2 more answers

According to the scatterplot below, which statement is correct? A graph titled Courses Completed versus Remaining Credits Needed

kondaur [170]

Answer:

Option B.

Step-by-step explanation:

It is given that a graph titled Courses Completed versus Remaining Credits Needed to Graduate has courses completed on the x-axis and Credits need to graduate on the y-axis.

Points plotted are (4, 110), (8, 76), (16, 63), (20, 53), (24, 33).

Since, x-axis represents the courses completed, therefore the input, or independent variable is courses completed.

Since, y-axis represents the Credits need to graduate, therefore the output, or dependent variable is Credits need to graduate.

Therefore, the correct option is B.

6 0

3 years ago

Read 2 more answers