All categories

2 years ago

Least two digit number exactly divisible by 6

Mathematics

2 answers:

sp2606 [1]2 years ago

8 0

Answer:

2 and 3

Step-by-step explanation:

Mumz [18]2 years ago

5 0

Answer:

2 and 3 are divisible by 6..

You might be interested in

500(x – 3) = 5,000 What’s the value of x?

Vladimir79 [104]

Answer:

Step-by-step explanation:

500(x-3)=5000

500x-1500=5000

500x=5000+1500

500x=6500 /:500

x=13

4 0

3 years ago

Read 2 more answers

A drama class has a total of 40 students. The number of males is 6 more than the number of females. How many males and how many

Lady_Fox [76]

Answer:

Females = 17 and males = 23

Step-by-step explanation:

Given that,

Total no of students in the class = 40

Let no. of females = x

No. of males = 6+x

ATQ,

Total students = males + females

40 = x+6+x

40-6 = 2x

34 = 2x

x = 17

Hence, there are 17 females and (6+17= 23) males.

7 0

3 years ago

It's solving multi-step inequalities

babymother [125]

H is less than or equal to 35

Just simplify each side and solve for the variable.

4 0

2 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

2 years ago

Evaluate C(n, n). A. 0 B. 1 C. n

horrorfan [7]

$C(n,n)=\dfrac{n!}{n!(n-n)!}=\dfrac1{0!}=\dfrac11=1$

In other words, how many ways are there to choose $n$ objects from a total of $n$ objects? Just one; take all of them at the same time.

4 0

3 years ago

Least two digit number exactly divisible by 6​

Least two digit number exactly divisible by 6