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GrogVix [38]
3 years ago
9

A one-tailed test is a a. hypothesis test in which rejection region is in one tail of the sampling distribution b. hypothesis te

st in which rejection region is in both tails of the sampling distribution c. hypothesis test in which rejection region is only in the lower tail of the sampling distribution d. hypothesis test in which rejection region is only in the upper tail of the sampling distribution
Mathematics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

Step-by-step explanation:

One Tailed Test:

  • A one tailed test is a test that have hypothesis of the form

H_0: \bar{x} = \mu\\H_A: \bar{x} < \mu\text{ or } \bar{x} > \mu

  • A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
  • Rejection region is the area for which the null hypothesis is rejected.
  • If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.
  • If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.

Thus, for one tailed test,

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

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Step-by-step explanation:

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3 years ago
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Determine the value of a, b, and c for the quadratic equation: 4x2- 8x = 3
Rufina [12.5K]

Answer:

B. a = 4, b = -8, c = -3

Step-by-step explanation:

The quadratic equation given is:

4x^2- 8x = 3

The general form of a quadratic equation is given as:

ax^2 + bx +c = 0

Let us put the given equation in this form and then compare with the general form of the quadratic equation.

4x^2- 8x = 3\\\\4x^2 - 8x - 3 = 0

Therefore, by comparing:

a = 4

b = -8

c = -3

The correct option is B

4 0
3 years ago
G verify that the divergence theorem is true for the vector field f on the region
Alenkasestr [34]
\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1

Converting to spherical coordinates, we have

\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi

On the other hand, we can parameterize the boundary of E by

\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle

with 0\le u\le2\pi and 0\le v\le\pi. Now, consider the surface element

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv
=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi

as required.
3 0
3 years ago
I need help I have no clue
Setler79 [48]

Answer:

The answer to your question is x = 64; y = 20

Step-by-step explanation:

Angles    2x + 2  and 130° are vertical angles so they measure the same.

                           2x + 2 = 130

- Solve for x

                           2x = 130 - 2

                           2x = 128

                             x = 128/2

                             x = 64

Angles  3y - 10 and 50° are vertical angles, so they measure the same.

                           3y - 10 = 50

                           3y = 50 + 10

                           3y = 60

                             y = 60/3

                            y = 20

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Together, their probabilities are 1/26(1/25) = 1/650
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