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On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.
From the question it follows that line MK bisects angle ∠JKL into ∠JKM & ∠MKL where M is the point in the interior of ∠JKL.
Therefore, as we have given m∠JKL = 84 & m∠MKL = 42
and we have to find m∠JKM , we will simply write the equation as follow
m∠JKL = m∠JKM + m∠MKL
Inserting values we get,
84 = m∠JKM + 42
m∠JKM = 42
Hence, angle m∠JKM of the triangle ΔJKL is 42.
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Answer:
The answer is 4
Step-by-step explanation:
Answer:
what is the step by step of 1/ cos x csc^2 x = sin x/ cot x
Step-by-step explanation:
1
.
csc
x
=
1
sin
x
2
.
cot
x
=
cos
x
sin
x
Given,
1
−
cos
x
sin
x
=
csc
x
−
cot
x
Simplify the right side.
csc
x
−
cot
x
=
1
sin
x
−
cos
x
sin
x
=
1
−
cos
x
sin
x
∴
, LS
=
RS.
