All categories

3 years ago

What is the term for this question?

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

5 0

(23+10)/2.75 = 12 is the answer

You might be interested in

Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)

Gnom [1K]

Answer: Horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

Step-by-step explanation:

Since we have given that

$y=\dfrac{x^2-9}{4x^2+1}$

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is $4x^2+1$

Now,

$4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}$

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

$y=\dfrac{1}{4}$

Hence, horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

8 0

3 years ago

The perimeter of a regular 4-sided polygon (square) is 48 units and the length of each side is x +1 units. What is the value of

iren [92.7K]

Answer:

x=11

Step-by-step explanation:

48-4=44

44/4=11

x=11

11+1=12

12•4= 48

6 0

3 years ago

Read 2 more answers

Alexa programmed a website's checkout process with an equation to calculate the amount customers will be charged when they buy h

Tamiku [17]

Answer:

Hey there!

The equation would be C=3.50r+5.75

Let me know if this helps :)

5 0

3 years ago

Paul is going to install tiles on the floor of a swimming pool. The swimming pool is 15 meters long by 7 meters wide. A tile cos

irakobra [83]

So we know that the swimming pool is 15 by 7 meters wide.
15 times 7 is 105.
Now, a tile costs $6 and covers 1 square meter.
So, we should multiply 105 by 6, which would give us 630.

So, if I'm correct, the answer should be that it costs him $630 to install the tiles on the swimming pool.
(sorry if I'm incorrect)

5 0

3 years ago

Read 2 more answers

Aria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there wer

denpristay [2]

Answer:

8,800,000cars

Step-by-step explanation:

Given the initial amount of cars = 80,000,000

If there is 10 % increase in the first year;

Increment = 10% of 80,000,000

Increment = 0.1 * 80,000,000

Increment = 8,000,000

Amount of car in year 2 = 80million + 8million = 88million

Year3;

Amount of car in year 3 = 88,000,000+(10%of88million)

Amount of car in year 3 = 88,000,000+8,800,000

Amount of car in year 3 =96,800,000

Differences in the number of cars = 96,800,000 - 88,000,000

Differences in the number of cars = 8,800,000cars

<em>Hence there are 8,800,000cars in years 3 than year 2</em>

7 0

3 years ago