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denis-greek [22]
2 years ago
12

What is the term for this question?

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
5 0
(23+10)/2.75 = 12 is the answer
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A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r
weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

6 0
3 years ago
what is the equation (in slope-intercept form) of a line that passes through the point (3,-2) and has a slope of -2
Tpy6a [65]

Answer:

y =  - 2x + 4

Step-by-step explanation:

Thank you

5 0
1 year ago
Martin can travel 174 miles in 3 hours. At this rate, how far can he travel in 7.
Blizzard [7]

Answer:

I believe the answer is 406 miles.

Let me know of this is the correct answer

7 0
2 years ago
Please quickly! Out of 5,500 people who attended the football game, fifty-six percent were rooting for the home team. How many p
tigry1 [53]
3,080 people rooted for the hometeam.
5 0
2 years ago
Thee population of a town, P(t), is 2000 in the year 2010. Every year, it increases by 1.5%. Write an equation for the populatio
steposvetlana [31]

Given:

In 2010, the population of a town = 2000

Every year, it increase by 1.5%

To find the equation P(t) which represents the population of this town t years from 2010.

Formula

If a be the original population of a town and it increases by b% every year, after t year the population will be

a (1+\frac{b}{100} )^{t}

Now,

Taking, a  =2000, b = 1.5 we get,

P(t) = 2000(1+\frac{1.5}{100} )^{t}

or, P(t) = 2000(1+0.015)^{t}

Hence,

The population of this town t years from 2010 P(t) = 2000(1+0.015)^{t}, Option D.

7 0
3 years ago
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