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aivan3 [116]
3 years ago
6

Evelyn has $524.96 in her checking account. She must maintain a $500 balance to avoid a fee. She wrote a check for $32.50 today.

Write an inequality that would be used to solve for the least amount of money she needs to deposit to avoid a fee. 524.96 − 32.50 + x ≥ 500 524.96 − 32.50 + x ≤ 500 524.96 + 32.50 − x ≥ 500 524.96 + 32.50 − x ≤ 500
Mathematics
1 answer:
barxatty [35]3 years ago
4 0

Answer:

524.96 − 32.50 + x ≥ 500

Amount need to deposit = $7.54

Step-by-step explanation:

Given:

Amount in checking account = $524.96

Maintain amount = $500

Amount of check = $32.50

Find:

Amount need to deposit

Computation:

Assume, amount need to deposit = x

So,

For avoiding fee

524.96 − 32.50 + x ≥ 500

x = 7.54

Amount need to deposit = $7.54

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Oil leaks out of a tanker at a rate of r=f(t) liters per minute, where t is in minutes. If f(t) = A e^{-k t}, write a definite i
8_murik_8 [283]

Answer:

V_{total} = \displaystyle\int_0^{60} A e^{-k t}~dt

Step-by-step explanation:

We are given the following in the question:

Oil leaks out of a tanker at a rate of r = f(t) liters per minute, where t is in minutes.

f(t) = A e^{-k t}

Let V be the volume, then we are given that rate of leakage is:

\displaystyle\frac{dV}{dt} = f(t) = A e^{-k t}

Thus, we can write:

dV = f(t).dt = A e^{-k t}~dt

We have to find the  a definite integral expressing the total quantity of oil which leaks out of the tanker in the first hour.

Thus, total amount of oil leaked will be the definite integral from 0 minutes to 60 minutes.

dV =A e^{-k t}~dt\\V_{total} = \displaystyle\int_a^b f(t)~dt\\\\a = 0\text{ minutes}\\b = 60\text{ minutes}\\\\V_{total} = \displaystyle\int_0^{60} A e^{-k t}~dt

The units of integral will be liters.

5 0
3 years ago
Solve the equation <br><br> 3(x+2) = 2(2 - x)
RideAnS [48]

Answer:

x=-2/5

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
H=3+14t-5t^2 <br> What is its maximum height
timurjin [86]

Answer:

12.8

Step-by-step explanation:

Given a parabola in standard form , ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

h = 3 + 14t - 5t² ← is in standard form

with a = - 5 and b = 14, thus

x_{vertex} = - \frac{14}{-10} = 1.4

Substitute t = 1.4 into h for maximum height

h = 3 + 14(1.4) - 5(1.4)²

   = 3 + 19.6 - 9.8 = 12.8

5 0
4 years ago
Solve the following system of equations. Show all work and solutions.
Hitman42 [59]
  • y=2x²+6x+1
  • y=-4x²+1

Make the equations equal and solve for x

  • 2x²+6x+1=-4x²+1
  • 6x²+6x=0
  • 6x(x+1)=0
  • 6x=0 or x+1=0
  • x=0 or x=-1

For x=0

  • y=-4(0)+1=1

For x=-1

  • y=-4(1)+1=-3

The solutions are

  • (0,1) and (-1,-3)

Graph attached

4 0
2 years ago
A rectangle is three centimeters.longer than it is wide. if its length were to be decreased by two centimeters, its area would d
Scorpion4ik [409]
Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30

substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w

substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w

substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15

insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16

B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2


7 0
4 years ago
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