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kozerog [31]
3 years ago
10

0=(x-8) (3x-5) show all work

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0

Answer:

x = 8

x=1\frac{2}{3}

Step-by-step explanation:

0 = (x - 8)(3x - 5)

(x - 8)(3x - 5) = 0

x(3x - 5) - 8(3x - 5) = 0

3x² - 5x - 8(3x - 5) = 0

3x² - 5x - 24x + 40 = 0

3x² - 29x + 40 = 0

x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

Ignore the A before the ±. It wouldn't let me type it correctly.

3x² - 29x + 40 = 0

a = 3

b = - 29

c = 40

x=\frac{-(-29)±\sqrt{(-29)^{2}-4((3)(40)) } }{2(3)}

x=\frac{-(-29)±\sqrt{841-4((3)(40)) } }{2(3)}

x=\frac{29±\sqrt{841-480} }{2(3)}

x=\frac{29±\sqrt{361} }{2(3)}

x=\frac{29±19 }{2(3)}

x=\frac{29±19 }{6}

Two separate equations

x=\frac{29+19 }{6}

x=\frac{48 }{6}

x = 8

x=\frac{29-19 }{6}

x=\frac{10 }{6}

x=\frac{5 }{3}

x=1\frac{2}{3}

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