It is C i believe you plug in the answers to get it
Answer:
<h2>A</h2>
Step-by-step explanation:
y > 0 - the region above the line together with that line
y ≥ 0 - the region above the line together with that line
y < 0 - the region below the line without that line
y ≤ 0 - the region below the line together with that line
We have:
y > 2 - the region above the line together with that line
y ≥ 2x - 3 - the region above the line together with that line
<em>look at the picture</em>
The common part is the solution.
The quadratic formula is ![\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%5B2%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
and in the equation ax^2+bx+c=0
so now all you have to do is substitute the numbers into the quadratic formula
Answer:
Step-by-step explanation:
If one angle = 90 degrees, then the other 2 added together must also = 90.
There is only 1 answer to this, since the triangle is isosceles..
x + x = 90 Combine
2x = 90 Divide by 2
x = 90/2
x = 45
So both acute angles = 45 degrees.