In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer:
First
Step-by-step explanation:
You write down the decimal fraction like say .75 you put .75/1. Then you multiply both sides by 100 so .75/1 would turn into 75/100. Then all you have to do is simplify the fraction.
Answer:
Step-by-step explanation:
yes, since that are 2 points:
y-int is (0, y)
x-int is (x, 0)
since you need only two points for a function with no restrictions, we can use y and x intercepts as points
Answer:

Step-by-step explanation:
The first line has a slope of -5/3 found using the points in the slope formula.

Parallel lines have the same slope. So -5/3 is the slope of the second line. Write its equation using the point slope form
.
