1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
g100num [7]
3 years ago
12

A) in a right-angled triangle, if hypotenuse is 20 cm and the

Mathematics
1 answer:
Bond [772]3 years ago
6 0

Answer:

Step-by-step explanation:

Ratio = 4 :3

Other two sides = 4x , 3x

Pythagorean theorem

(4x)²  + (3x)² = 20²

16x² + 9x²  = 400

          25x² = 400

             x² = 400 ÷ 25

            x²  = 16

             x = √16

x = 4 cm

4x = 4*4 = 16

3x = 3*4 = 12

Sides = 16cm  , 12 cm

You might be interested in
At a store, cartons of whole milk costs $10.50 and 5 cartons of fat free milk costs $5.00. How much would it cost to buy 3 carto
Lostsunrise [7]

Answer:

$31.50

Step-by-step explanation:

7 0
3 years ago
1+1000000000000000000000
solniwko [45]

Answer:

1000000000000000000001

Step-by-step explanation:

Done. You're welcome

4 0
3 years ago
Read 2 more answers
What is the equation of the lines -6,-4 & 4,6
Jet001 [13]
1. use the equation y -y1 = m(x-x1)
2. (-6,-4) is x1,y1 and (4,-6) is x2,y2
3. y-(-4) = m(x-(-6)
m is the gradient, 10/10, which is 1. make two negatives into a positive.
4. y+4 = x+6

therefore the equation of the lines is y = x+2

substitute the points back into the equation to double check.
6 0
3 years ago
Help me. I'll mark brainiest
enot [183]
X^2 - 6x + 9 = 25 + 9
5 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
Basile [38]

The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

brainly.com/question/14487937

#SPJ4

6 0
2 years ago
Other questions:
  • Josiah went to the local barber to get his hair cut. It cost $18 for the haircut. Josiah tipped the barber 15%. What was the tot
    15·2 answers
  • What is the greatest common factor of 18s+54
    8·2 answers
  • Find the derivative of the following functions:
    10·1 answer
  • I have 1hundreds, 9tens, 9 o es, 8 rentas. What Number am I ?
    7·1 answer
  • A sphere has a radius of 4 in. which equation finds the volume of the sphere?
    7·1 answer
  • HELP ME PLS ! 20 POINTS
    10·2 answers
  • Find the point at which the line f(x)=3x-15 intersects the line g(x)= -4x+13
    11·1 answer
  • Can Someone help me please!
    12·2 answers
  • Help please!!!!..............
    15·2 answers
  • Amaia purchased two blouses for $12.50 each and a skirt for $11.25. The sales tax rate is 8.5%. How much total sales tax will Am
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!