Answer:
48π or 150.72
Step-by-step explanation:
The radius of the big circle is 8.
We can use that to find the area of the big circle.
Area is πr^2
π(8)^2
64π
Now, we can find the area of the small circle.
The diameter of that is 8, meaning the radius is 4.
πr^2
π(4)^2
16π
Now we subtract the area of the small circle from the area of the big circle to get the area of the shaded region.
64π-16π=48π
As a decimal: 48*3.14=150.72
Answer:
Length of rectangular strip = 12
area of rectangular strip = 2*12 = 24
Area of square = x^2 = 12^2 = 144
Step-by-step explanation:
Area of square x^2
area of rectangle is given by length * width
Length of rectangular strip = x
width of rectangular strip = 2
area of rectangular strip = length * width = 2*x = 2x
Area of square piece of paper when rectangular strip is taken away from it
= Area of square - area of rectangular strip
= 
It is given that Area of square piece of paper when rectangular strip is taken away from it is 120 square units.
Thus,

Thus,
either x+10 = 0 or x -12= 0
x = -10 or x = 12
but length cannot be negative hence neglecting x = -10
hence value of x is 12.
Hence,
Length of rectangular strip = 12
area of rectangular strip = 2*12 = 24
Area of square = x^2 = 12^2 = 144
Answer:
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Step-by-step explanation:

Step-by-step explanation:







