Make use of prime factorizations:
Both terms have a common factor of :
- - -
The second one is not true! We can write
Both terms have a common factor of :
Since , and , we'd still have to show that is a multiple of 6. This is impossible, because and there is no multiple of 2 that can be factored out.
M < 2 = m < 6...corresponding angles
m < 5 = m < 8....vertical angles are congruent
1) <span>Pairs A(2, 5), B(6, 5), and C(6, 1)
point D
Dx=Cx-(Bx-Ax)=(6-(6-2))=2
Dy=Cy=1
</span>the coordinates of vertex D is (2,1)
2) Pairs <span>A(2, 3), B(7, 3), and C(7, -2)
</span>point D
Dx=Cx-(Bx-Ax)=(7-(7-2))=2
Dy=Cy=-2
the coordinates of vertex D is (2,-2)
3) Pairs <span>A(-5, -1), B(1, -1), and C(1, -5)
</span>point D
Dx=Cx-(Bx-Ax)=(1-(1+5))=-5
Dy=Cy=-5
the coordinates of vertex D is (-5,-5)
4) Pairs <span>A(-1, 4), B(7, 4), and C(7, -1)
</span>point D
Dx=Cx-(Bx-Ax)=(7-(7+1))=-1
Dy=Cy=-1
the coordinates of vertex D is (-1,-1)