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Bezzdna [24]
2 years ago
6

Which is the sum of -4 and its additive inverse?

Mathematics
2 answers:
Aneli [31]2 years ago
3 0

Answer:

-4 +4 =0

Step-by-step explanation:

The sum of a number and its' additive inverse is 0

The additive inverse of -4 is 4

-4 +4 =0

notka56 [123]2 years ago
3 0

The answer is "4, -4, 0".

Hope this helps.

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Is 10 thousands, 5 hundreds greater than or less than 1,050 tens
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Its greater than 1,050 tens.
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Help with this work pls​
Travka [436]

Answer:

  (6, 2), (0, -2), (-3, -4)

Step-by-step explanation:

The intercepts are clearly (0, -2) and (3, 0). This eliminates the bottom two choices.

Both of these are listed in the upper left choice, but the third point there, (-6, -5), is not on the graph. This leaves only the upper right choice. Checking the remaining two points in that choice, (6, 2) and (-3, -4), confirms they are both on the graph.

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2 years ago
What does 2 (p -q) +5 (p+q) equal when p = 7 and q = -2? Answer:​
salantis [7]

Answer:

43

Step-by-step explanation:

Given

2(p - q) + 5(p + q) ← substitute p = 7 and q = - 2 into the expression

= 2(7 - (- 2)) + 5(7 + (- 2))

= 2(7 + 2) + 5(7 - 2)

= 2(9) + 5(5)

= 18 + 25

= 43

7 0
3 years ago
Need help as soon as possible!<br><br> What is the value of g(3)?<br><br> 2<br> 3<br> 9<br> 14
Alex777 [14]

g(x) is a piecewise function in such a way that it changes how it's defined based on what x happens to be. There are three cases

Case A: g(x) = x-1 but only if -2 \le x < -1 (x is between -2 and -1; including -2 but excluding -1)

Case B: g(x) = 2x+3 but only when -1 \le x < 3 (x is between -1 and 3; including -1 but excluding 3)

Case C: g(x) = 6-x but only when x \ge 3

The input is x = 3 since we want to find the value of g(3). So we look at the 3 cases above (A,B,C) and determine that we use case C. Why? Because x = 3 makes x \ge 3 true. Put another way, x = 3 is in the interval [3, infinty). So we'll use g(x) = 6-x to find that...

g(x) = 6-x

g(3) = 6-3

g(3) = 3

Answer: 3

5 0
3 years ago
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