Comparing the temperature of a coolant before and after use in a machining process.
Step-by-step explanation:
The temperature of a coolant in the polar region was found to be modeled by the equation t=(8x-55)° where t is the final fluid temperature after being used for cooling ,x is the time the fluid is applied on the cutting edge and -55 is the normal temperature of the fluids used for cooling processes in a machine garage.
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Integers :brainly.com/question/102082
Keyword : integer
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3x+x+20 = 180
4x = 180-20
4x = 160
x = 40
×+20+3x+2x+38+C=360
40+20+3×40+2×40+38+C=360
40+20+120+80+38+C=360
298+C=360
C=360-298
C =62°
Which question are you talking about 1 or 2?
Answer:
(3,1) --> One solution
Step-by-step explanation:
Start by multiplying the first equation by 4:
-7x(4)+2y(4)=-19(4)
-28x+8y=-76
In this scenario, we can eliminate 8y by subtracting the two equations:
-34x=-102
Divide both sides by -34
x=3
Plug 3 back in for x to solve for y
-7(3)+2y=-19
-21+2y=-19
Add 21 to both sides
2y=2
Divide both sides by 2
y=1
(x,y)=(3,1)
