It’s due late tonight can some pls help me pass

CAN SOMEONE PLEASE DO THIS IF I DONT I WILL FAIL 8TH GRADE PLZ HELP ILL GIVE ALL MY POINTS PLZZZZZ HELP ILL DO ANYTHING PLZ :(((

Dmitrij [34]

Answer:

what am i suppose to help with

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help meeeeeeeeeeeeeeeee please

Harman [31]

9514 1404 393

Answer:

2.1 ft³

Step-by-step explanation:

Put the given radius and height into the volume formula and do the arithmetic.

V = 1/3πr²h

V = 1/3(3.14159)(1 ft)²(2 ft) ≈ 2.094 ft³

Rounded to tenths, this is 2.1 cubic feet.

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The picture cuts off your rounding requirements. If it is hundredths, you need to use 2.09 ft³. If it is thousandths, your answer will depend on the value of pi you are asked to use.

4 0

3 years ago

You are traveling down a country road at a rate of 95 feet/sec when you see a large cow 300 feet in front of you and directly in

emmainna [20.7K]

Answer:

1) You can rely solely on your brakes because when doing so the car will just travel 250ft from the point you hit your brakes till the point the car stopped completely, leaving you 50ft away from the cow.

2) See attached picture.

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in $ft/s^{2}$

3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) $j(t)=\left \{ {{95t-9t^{2}; 0\le t$

$j'(t)=\left \{ {{95-18t; 0\leq t$

(see attached picture for graph)

Step-by-step explanation:

1) In this part of the problem we need to find the time when the speed of the car is 0. Gets to a complete stop. For this we will need to take the derivative of the position function so we get:

$j(t)=95t-9t^2$

$j'(t)=95-18t$

and we set the first derivative equal to zero so we get:

95-18t=0

and solve for t

-18t=-95

$t=\frac{95}{18}$

t=5.28s

so now we calculate the position of the car after 5.28 seconds, so we get:

$j(5.28)=95(5.28)-9(5.28)^{2}$

$j(5.28)=250.69ft$

so we have that the car will stop 250.69ft after he hit the brakes, so there will be about 50ft between the car and the cow when the car stops completely, so he can rely just on the breaks.

2) For answer 2 I take the second derivative of the function so I get:

$j(t)=95t-9t^{2}$

$j'(t)=95-18t$

j"(t)=-18

and then we graph them. (See attached picture)

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in $ft/s^{2}$

3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) $j(t)=\left \{ {{95t-9t^{2}; 0\le t$

$j'(t)=\left \{ {{95-18t; 0\leq t$

(see attached picture for graph)

5 0

3 years ago

N - 3/5= 1/4 please answer

Brut [27]

I think it’s 17/20. i hope i helped

4 0

4 years ago

Read 2 more answers

Can someone explain how to solve x<br><br> 2(x+10)=20

trapecia [35]

So first you are going to want simplify the left side of the “=“ sign by multiplying the number outside the parenthesis, 2, by the numbers inside the parenthesis, (x+10). So, 2*x= 2x and 2*10=20. Bringing you to 2x+20=20, from here you want to isolate the variable, 2x, so you have to subtract 20 from both sides to do so. This brings you to 2x=0, when a variable is equal to zero, in specific problems, like this one, it is right, but always make sure to check your answer because in some problems when the variable is equal to 0 the answer is sometimes No Solution, so be careful. The way you want to be sure that x=0 in this equation is the plug it into the original equation, 2(x+10)=20, so it would be, 2(0+10)=20 and this goes to 2(10)=20, multiply the outside number to the inside which gives you 20 so then 20=20. It matches so it’s correct, THE ANSWER IS x=0, sorry if I made it complicated.

6 0

3 years ago